Answer:
3.6 kHz
Explanation:
The pipes behave like a closed pipe . The end open is the end of the air canal outside the ear and the closed end is the eardrum.
The first harmonic will be as seen in the figure attached.
The length of the first harmonic will be λ/4.
λ/4=2.4 cm
λ=2.4 * 4=9.6 cm 0.096 m
Speed of Sound- 344 m/s(in air)
velocity(v) * Time Period(T) = Wavelength (λ)
Also, Time Period(T)= \frac{\textrm{1}}{\textrm{Frequency(f)}}
\frac{\textrm{Velocity}}{\textrm{Wavelength}}=\frac{\textrm{1}}{\textrm{Time Period}} =Frequency
Plugging in the values into the equation,
Frequency = Hz
= 3583.3 Hz≈3600 Hz= 3.6 kHz
Frequency= 3.6 kHz
Consider horizontal component:
Using the formula:v2=u2+2a<span>s</span>
<span>0=(16sin<span>470</span><span>)2</span>+2(−9.81)s</span><span>s=6.98m</span><span>=7.0m(2s.f.)</span>The maximu height from the ground is 8.5m
Answer:
Newton gives us force
F=-G*M*m/R^2
Divide by the mass of the object to get acceleration
a=F/m = GM/R^2
You are solving the distance where the force from the moon equals the force from the Earth -
a= G*(mass of earth)/R^2 - G*(mass of moon)/(384400000-R)^2=0
Or in other words
G*(mass of earth)/R^2=G*(mass of moon)/(384400000-R)^2
Divide by G*(mass of the moon) and multiply by R^2 to get terms on both sides
G*(mass of earth)/(G*(mass of moon))=R^2/(384400000-R)^2
Since the mass of the moon and earth are fixed, the left side is a number
81.3 = R^2/(384400000-R)^2 → R^2/(384400000-R)^2–81.3 = 0
simplify
R/(384400000-R) = 9.01665
R=346024000 = 346,024 km.
Explanation:
Answer:
Mass is the quantity of matter contained in a body. The mass of an object is measured in kilogram (kg).
Explanation:
Answer:
5.11 s
Explanation:
Given:
v₀ = 0 m/s
y₀ = 128 m
y = 0 m
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
(0 m) = (128 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 5.11 s