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mamaluj [8]
3 years ago
12

Determine two ways power can be increased?

Physics
2 answers:
Furkat [3]3 years ago
7 0
Do more work in the same time or do the same work in less time
Dmitriy789 [7]3 years ago
4 0
Hello,

Your answer would be:

Power is the rate at which work is done. Therefore to increase it either:
- Do more work in the same time.
- Do the same work in less time.

Plz mark me brainliest!

Hope this helps!
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The wing of an airplane experiences the forces as depicted in the vector diagram to the right. Using both one and two dimensiona
Vedmedyk [2.9K]

Answer:

A.) 3605.6 N

B.) 33.7 degree

Explanation:

To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components

Resolving into x component :

Sum of forces = 3500 - 500 = 3000N

Resolving into y component:

Sum of forces = 2000N

Resultant force Fr = sqrt ( Fx^2 + Fy^2)

Fr = sqrt ( 3000^2 + 2000^2 )

Fr = sqrt ( 9000000 + 4000000 )

Fr = sqrt ( 13000000)

Fr = 3605.6 N

Therefore, resultant force acting on the wing is 3605.6 N

The direction of the vector will be:

Tan Ø = Fy / Fx

Substitute Fx and Fy into the formula

Tan Ø = 2000 / 3000

Tan Ø = 0.66666

Ø = tan^-1(0. 66666)

Ø = 33.7 degree.

6 0
3 years ago
Calculate the maximal friction force for a parked car between the rubber tires and a wet street. Assume the car’s mass is 1600 k
NikAS [45]

Answer:

Fr=12544N

Explanation:

1. Find the equation of eht maximal friction force:

The maximal friction force is given by the equation Fr=usmg, where μs is the static friction coefficient, m is the car´s mass and g is the gravitational force.

2. Replace values in the equation to find the answer:

Fr=0.8*1600kg*9.8\frac{m}{s^{2}}

Fr=12544N

5 0
3 years ago
What is the relationship between the temperature of a star and its luminosity?
Sladkaya [172]
The Luminosity of a star is proportional to its Effective Temperature to the 4th power and its Radius squared.
3 0
3 years ago
Questions<br> 2.<br> Rewrite the following quantities using suitable<br> prefixes<br><br> 5000 000
Rufina [12.5K]
Ans. 5 X 10^6

Explanation:

Here,^ represents 6 times 10 and 5 is multiplied. That is 5000 000.

Hope this helps
5 0
3 years ago
the end of the tracks, 8.8 m lower vertically, is a horizontally situated spring with constant 5 × 105 N/m. The acceleration of
devlian [24]

Answer

Assuming the mass of the car, m = 43000 kg

initial speed u = 0

vertical distance moved, h = 8.8 m

spring constant k = 5 x  10⁵ N / m

acceleration of gravity = 9.8 m/s²

From law of conservation of energy ,

Gravitational potential energy at starting position =potential energy of the spring at maximum compression

                m g h =\dfrac{1}{2}k x^2

                x = \sqrt{\dfrac{2mgh}{k}}

                x = \sqrt{\dfrac{2\times 43000\times 9.8\times 8.8}{5\times 10^5}}

                    x = 14.83 m

If the mass of the car is equal to 43000 Kg the spring is compressed to 14.83 m

6 0
4 years ago
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