Answer:
The answer to your question is 2.32 atm
Explanation:
Data
P = ?
n = 0.214
V = 2.53 L
T = 61°C
R = 0.082 atm L/mol°K
Formula
PV = nTR
solve for P
P = nRT/V
Process
1.- Calculate the temperature in K
°K = °C + 273
°K = 61 + 273
= 334
2.- Substitution
P = (0.214 x 0.082 x 334) / 2.53
3.- Simplification
P = 5.86/2.53
4.- Result
P = 2.32 atm
Answer:
Electrons are particles that surround the nucleus of an atom like a cloud. As with protons and neutrons, electrons are essential to an atom's structure.
You have the stoichiometric equation. This tells you unequivocally that an
18
⋅
g
mass of water, 1 mole, reacts with a
56.07
⋅
g
mass of quicklime to form a
74.09
⋅
g
mass of slaked lime.
If you don't from where I am getting these numbers, you should know, and someone will be willing to elaborate.
Here, you have formed
6.21
⋅
m
o
l
of quicklime which requires stoichiometric lime AND water. And thus you need a mass of
6.21
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
water
≅
88
⋅
g
.
In practice, of course I would not weigh out this mass. I would just pour
100
−
200
⋅
m
L
of water into the lime.
Electronegativity is the tendency of the element to attract shared pair of electron towards itself in bonded condition.
Ionisation enrgy is the amount of energy required to remove the outermost electron from neutral gaseous atom
