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hjlf
2 years ago
13

you work at a Dave's donut shop the shop sells a dozen donuts for 6.99 dollars Dave redesigned the Box used to hold one dozen do

nuts you have been asked to determine whether the company should use the new box or keep the original box the table shows the dimensional of each box and the cost per square foot of cardboard to make each box box original length in 10 waste in six height in three cost per square foot dollar 0.22 new length in 15 waste it with in 11 ties into cost per square foot dollar 0.15 what is the surface area in square inches of the original box? please help I really need help with my work ​
Physics
2 answers:
Fofino [41]2 years ago
7 0

Answer:

A box of donuts would cost: b = 3.84 + 0.18f

First, we have to find the total cost of the donuts.

12 x 0.32 = 3.84

Next, we need to determine the cost of the box. However, we don't know the surface area, just the cost per foot. We can multiply the number of square feet of the box by $0.18 to find the cost.

So our equation could be:  b = 3.84 + 0.18f (where f is the surface area of the box in square feet)Explanation:

alexira [117]2 years ago
6 0

Answer:

The original box is 180 Inches², the new box is 330 inches²

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nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

\rho = \frac{m}{V}

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

\rho = \frac{277}{370}\approx0.75

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0
3 years ago
Read 2 more answers
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
3 years ago
When waves superimpose and make bigger amplitudes what form of interference is that
eimsori [14]

Answer:

Constructive Interference

Explanation:

Constructive Interference occurs when two waves superimpose and make bigger amplitudes.

In constructive interference, the crests of one wave fall on the crests of second wave and the amplitudes add up. The amplitude of the resultant wave is equal to sum of the amplitude of the individual waves. Similarly, the trough of first wave falls on the trough of other wave and they superimpose to create the trough of the resultant wave.

For Example, In the attachment, two waves A and B superimpose and demonstrate Constructive interference to create the wave C.

7 0
3 years ago
I need help this is for economics, can anyone help me ?
PolarNik [594]

i can <u>when do u need it by</u> working on it now!!!

4 0
3 years ago
You are testing a new amusement park roller coaster with an empty car with a mass 120 kg. One part of the track is a vertical lo
Kay [80]

Answer:

- 5436 J

Explanation:

mass of car, m = 120 kg

radius of loop, r = 12 m

velocity at the bottom (A) = Va = 25 m/s

Velocity at the top(B) = Vb = 8 m/s

Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m

by use of Work energy theorem

Work done by all the forces = change in kinetic energy of the body

Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A

- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)

- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)

- 28224 + Work done by friction = - 33660

Work done by friction = -33660 + 28224 = - 5436 J

4 0
3 years ago
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