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hjlf
3 years ago
13

you work at a Dave's donut shop the shop sells a dozen donuts for 6.99 dollars Dave redesigned the Box used to hold one dozen do

nuts you have been asked to determine whether the company should use the new box or keep the original box the table shows the dimensional of each box and the cost per square foot of cardboard to make each box box original length in 10 waste in six height in three cost per square foot dollar 0.22 new length in 15 waste it with in 11 ties into cost per square foot dollar 0.15 what is the surface area in square inches of the original box? please help I really need help with my work ​
Physics
2 answers:
Fofino [41]3 years ago
7 0

Answer:

A box of donuts would cost: b = 3.84 + 0.18f

First, we have to find the total cost of the donuts.

12 x 0.32 = 3.84

Next, we need to determine the cost of the box. However, we don't know the surface area, just the cost per foot. We can multiply the number of square feet of the box by $0.18 to find the cost.

So our equation could be:  b = 3.84 + 0.18f (where f is the surface area of the box in square feet)Explanation:

alexira [117]3 years ago
6 0

Answer:

The original box is 180 Inches², the new box is 330 inches²

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A mass of 13kg stretches a spring 14cm. The mass is acted on by an external force of 6sin(t/2)N and moves in a medium that impar
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13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

#Where u is in meters and t in seconds.

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Given that :m=13.0kg, \ L=0.14m, \ F(t)=6sin\frac{t}{2}N, F_d(t*)=-4N^{-1}, u\prime(t*)=0.12m/s\\u(0)=0,u\prime(0)=0.04m/s

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\gamma=-\frac{F_d(t*)}{u\prime(t*)}=\frac{4N}{0.12m/s}\\=33.33Ns/m

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13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

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13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\, u in meters,t in seconds.

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