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djverab [1.8K]
3 years ago
12

A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t

ime between the person see and hear a firework explosion
Physics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

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7 0
3 years ago
Roller coasters accelerates from initial speed of 6.0 M/S2 final speed of 70 M/S over four seconds. What is the acceleration?
choli [55]

Answer:

a=16\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

The formula to calculate the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The roller coaster moves from vo=6 m/s to vf=70 m/s in t=4 seconds. To calculate the acceleration, solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

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\boxed{a=16\ m/s^2}

3 0
3 years ago
Does anyone know this one? Thanks
Inessa [10]

Answer:

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Explanation:

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384,400=3.844 \,*\,100,000= 3.844 \,*\,10^5

with a=3.844, and "5" as the exponent of ten (so b=5)

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Elena-2011 [213]

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so in order to find the speed of the cart we will first use energy conservation

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6 0
3 years ago
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