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xenn [34]
3 years ago
9

What is the percentage composition of CF4

Chemistry
2 answers:
adoni [48]3 years ago
8 0
The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>

<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Tpy6a [65]3 years ago
4 0

Answer:

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

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Answer:

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What is the purpose of the subscripts, or small numbers, in a chemical formula?
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A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?
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M( HCl) = ?

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number of moles HCl :

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</span>
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</span>
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= 0.007874 moles of HCl

M = n / V

M = 0.007874 / <span>0.0164

</span>= 0.480 M

Answer (2)

hope this helps!

4 0
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