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xenn [34]
3 years ago
9

What is the percentage composition of CF4

Chemistry
2 answers:
adoni [48]3 years ago
8 0
The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>

<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Tpy6a [65]3 years ago
4 0

Answer:

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

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The correct sequence where reactivity towards oxygen increases.
ziro4ka [17]

Answer:

Option D is good to go!

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Explanation:

3 0
3 years ago
How many moles are there in 3.612 x 1024 molecules of CaO?
melamori03 [73]

The number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

<h3>Number of moles in the molecules</h3>

The number of moles in  3.612 x 10²⁴ molecules of CaO is calculated as follows;

6.02 x 10²³ molecules = 1 mole

3.612 x 10²⁴ molecules = ?

= (3.612 x 10²⁴ ) / (6.02 x 10²³ )

= 6 moles

Thus, the number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

Learn more about number of moles here: brainly.com/question/15356425

3 0
2 years ago
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Georgia [21]
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3 0
3 years ago
Which of the following would form a cation? Ne Li O I
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5 0
3 years ago
Read 2 more answers
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -&gt; 2Fe(s) + 3CO(g)
Gelneren [198K]

Answer:

ΔS = +541.3Jmol⁻¹K⁻¹

Explanation:

Given parameters:

Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹

Standard Entropy of C = 5.7Jmol⁻¹K⁻¹

Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹

Standard Entropy of CO = 198Jmol⁻¹K⁻¹

To find the entropy change of the reaction, we first write a balanced reaction equation:

                              Fe₂O₃ +  3C →  2Fe + 3CO

To calculate the entropy change of the reaction we simply use the equation below:

      ΔS = ∑S_{products} - ∑S_{reactants}

Therefore:

     ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1

                          ΔS = +541.3Jmol⁻¹K⁻¹

5 0
3 years ago
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