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xenn [34]
3 years ago
9

What is the percentage composition of CF4

Chemistry
2 answers:
adoni [48]3 years ago
8 0
The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>

<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Tpy6a [65]3 years ago
4 0

Answer:

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

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A student was titrating the calcium and water solution and notice the formation of bubbles in the flask. which description would
labwork [276]
Hi!

When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:

CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻

HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O

The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃

4 0
3 years ago
What is the unit of Avogadro's number?
kompoz [17]

Answer:

it may be electron, atom or ions depend on the nature of the substance and the character of reaction

like :- particles per mole, coulombs per electron

8 0
3 years ago
How do the interactions that are broken in water when it is boiled compare with those broken when water is electrolyzed? Boiling
nasty-shy [4]

Answer:

Boiling water breaks intermolecular attractions and electrolysis breaks covalent bonds.

Explanation:

When water boils, hydrogen bonds are broken between adjacent water molecules. The hydrogen bond is an intermolecular bond between adjacent oxygen and hydrogen atoms of water molecules.  

During electrolysis, water dissociates in the presence of electric current. Here, ions are formed in the process. Therefore, covalent bonds are broken here.

8 0
3 years ago
What is the ph of a solution that results from mixing 25 ml of 0.15 M hcl to 25 ml of 0.52 m nh3?
BartSMP [9]

Answer:

7.00

Explanation:

When the solutions are mixed, the HCl dissociates to form the ions H+ and Cl-. The ion H+ will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H+ to 1 mol of Cl-, and 1 mol of H+ to 1 mol of NH3 to 1 mol of NH4+.

First, let's find the number of moles of each one of them, multiplying the concentration by the volume:

nH+ = 0.15 M * 25 mL = 3.75 mmol

nNH3 = 0.52 M * 25 mL = 13 mmol

So, all the H+ is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.

5 0
3 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
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