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xenn [34]
3 years ago
9

What is the percentage composition of CF4

Chemistry
2 answers:
adoni [48]3 years ago
8 0
The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>

<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Tpy6a [65]3 years ago
4 0

Answer:

C = 13.64%

F = 86.36% 

Explanation:

Percentage composition = (mass/molar mass) x 100

Molar mass of CF4 = 88 

C = 12g/mol

F = 19g/mol

C = 12/88 x 100 = 13.64% 

F = 76/88 x 100 = 86.36%

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3 years ago
Determine how many ml of water you need to remove, by evaporation, if you have a 500 ml of 10.20 M HNO3 dilute solution and you
Ludmilka [50]

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<h3>Dilution equation</h3>

Using the dilution equation:

M1V1 = M2V2

In this case, M1 = 500 mL, V1 = 10.20 M, M2 = 12 M

Substitute:

V2 = 500 x 10.20/12

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More on dilution can be found here: brainly.com/question/7208939

7 0
2 years ago
What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?
worty [1.4K]
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Current-

C-1            |        C-1
H-4            |         H-2
O-2            |         O-3


Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

<span>CH4 + 2O2 → CO2 + 2H2O</span>
C-1            |        C-1
H-4            |         H-4
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3 years ago
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