All categories

3 years ago

Repartos Equitativos: A:Repartir 21 chocolates en 5 niños (dividir) B:Repartir 10 chocolates en 3 niños (dividir)

Mathematics

1 answer:

lana [24]3 years ago

8 0

Respuesta:

4 1/5 bombones

3 1/3 bombones

Explicación paso a paso:

Distribuir 21 bombones entre 5 niños;

21/5 = 4 resto 1

Por lo tanto, se le da 4 chocolates a cada niño y el 1 chocolate restante se divide en 5 partes iguales y se le da 1/5 a cada niño. Por lo tanto, cada niño recibe 4 1/5 chocolates.

Distribuir 10 bombones entre 3 niños;

10/3 = 3 resto 1

Por lo tanto, se le da 3 chocolates a cada niño y el 1 chocolate restante se divide en 3 partes iguales y se le da 1/3 a cada niño. Por lo tanto, cada niño recibe 3 1/3 chocolates.

You might be interested in

Which type of visual aid best allow students to show a numerical information?

ryzh [129]

Graphs

°°°°°°°°°°°°°°°°

4 0

3 years ago

What should be the next number in the following series? 1 2 8 48 384

cluponka [151]

1
1 · 2 = 2
2 · 4 = 8
8 · 6 = 48
48 · 8 = 384
384 · 10 = 3840
3840 · 12 = 46080
46080 · 14 = 645120
...

$a_1=1;\ a_n=a_{n-1}\cdot(2n-2)$

3 0

3 years ago

Use addition to solve the linear system of equations. Include all of your work in your final answer. $\left\{ \right.$ 3x-y=6

ad-work [718]

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

$3x-y=6 \\y=x-4$

We can write second equation y=x-4 as: $-x+y=-4$

Let:

$3x-y=6--eq(1)\\ -x+y=-4--eq(2)$

Now, Adding equation 1 and 2

$3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1$

So, we get x = 1

Now, put value of x in second equation to find value of y:

$y=x-4\\Put\:x=1\\y=1-4\\y=-3$

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0

3 years ago

Write an equivalent expression for the following by combining like terms: 4y − y + 7y

Assoli18 [71]

4y - y + 7y

4y - y = 3y

3y + 7y = 10y

10y is your answer

hope this helps

4 0

3 years ago

In a clothing store, 65% of the customers buy a shirt, 30% of the customers

diamong [38]

Answer:

75%

Step-by-step explanation:

List out known probabilities

$\Pr(shirt) = 0.65 = \frac{65}{100} = \frac{13}{20}\\ \Pr(pants) = 0.40 = \frac{30}{100} = \frac{6}{20}\\\Pr(shirt \cap pants) = 0.20 = \frac{20}{100}=\frac{1}{5}$

recall equation

$\Pr(A \cup B)=\Pr(A)+\Pr(B)-\Pr(A \cap B)$

Plug in values

$\Pr(shirt \cup pants)=\frac{13}{20}+\frac{6}{20}-\frac{1}{5}\\\\therefore \Pr(shirt \cup pants) = \frac{15}{20} =\frac{3}{4} = 75\%$

4 0

3 years ago