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Iteru [2.4K]
3 years ago
10

If 5.9 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, how many liters of CO₂ is produced? (The density of CO₂ is

1.98 kg/m³ and 1 L = 1 dm³).

Chemistry
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

2.18 × 10³L

Explanation:

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Chuẩn Độ 15 ml dung dịch CH3COOH 0,2 m bằng dung dịch NaOH 0,2 m
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What kind of reaction occurs when you mix aqueous solutions of barium sulfide and sulfuric acid? what kind of reaction occurs wh
My name is Ann [436]

The kind of reaction that occurs when you mix aqueous solutions of barium sulfide and sulfuric acid is a precipitation reaction.

<h3>Further Explanation</h3>
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Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(aq) + 2H₂O(l)

  • This is a type of precipitation reaction, where a precipitate is formed after the reaction, that is Barium sulfate.
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  • These are reactions that involve reacting acids and bases or alkali to form salt and water as the only products.
  • For example a reaction between sodium hydroxide and sulfuric acid.

NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + H₂O(l)

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Mg(s) + CuSO₄(aq) → MgSO₄(aq) + Cu(s)

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Mg(s) + CuSO₄(aq) → MgSO₄(aq) + Cu(s)

  • Magnesium atom undergoes oxidation while copper ions undergoes reduction.
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  • These are type of reactions that involves breakdown of a compound into its constituents elements.
  • For example decomposition of lead nitrate.

Pb(NO3)2(S) → PbO(s) + O2(g) + NO2(g)

Keywords: Precipitation

<h3>Learn more about: </h3>
  • Precipitation reaction: brainly.com/question/11194650
  • Examples of precipitation reactions: brainly.com/question/11194650
  • Neutralization reactions brainly.com/question/3243813

Level: High school

Subject: Chemistry

Topic: Chemical reactions

Sub-topic: Precipitation reactions

3 0
3 years ago
Read 2 more answers
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
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