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bonufazy [111]
3 years ago
12

An object has one force acting on it. It is a 33- Newton force pointing downward. To create a net force of zero on the object, w

hich force must be applied to it?
Physics
1 answer:
Kamila [148]3 years ago
4 0

As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.

The answer is: A 33-Newton force pointing upward.

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Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot
labwork [276]

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

  • h is the height of fall
  • g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

  • v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

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6 0
2 years ago
An important difference between waves and classical particles is that A. waves cannot interfere. B. particles cannot interfere.
pishuonlain [190]
<span>C. waves can only interfere destructively. </span>
5 0
3 years ago
what is the period of a sound wave whose wavelength is 20.0m? use values from the book and show all of your work
Lera25 [3.4K]
The wavelength of a sound wave is related to its frequency by the relationship:
f= \frac{v}{\lambda}
where
f is the frequency
v is the speed of the wave
\lambda is the wavelength

The wave in our problem has wavelength of \lambda=20.0 m and speed of v=343 m/s (this is the speed of sound in air), therefore its frequency is
f= \frac{343 m/s}{20.0 m}=17.15 Hz

And the period of the wave is equal to the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{17.15 Hz}=0.058 s
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The answer is A. Iron.
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The mass needed at peg 1 is a 5g mass.

The 15g should hang at peg 5.

The reason is force x distance clockwise is equal to force x distance anti-clockwise
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