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igomit [66]
3 years ago
6

A projectile is launched with speed of 128 m/s, at an angle of 60° with the horizontal. After 2.0 s, what is the vertical compon

ent of the projectile's velocity?
After 2.0s, what is the speed of the projectile?​
Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

a) 91 m/s

b) 111 m/s

Explanation:

v = u + at

v = 128sin60 + (-9.8)(2.0) = 91.25125... m/s

v = √(vx² + vy²) = √((128cos60)² + 91.25125²) = 111.4575... m/s

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Answer:

a) y = 2.4 x 10⁻³ m = 0.24 cm

b) y = 3.2 x 10⁻³ m = 0.32 cm

Explanation:

The formula of Young's Double Slit experiment will be used here:

y = \frac{\lambda L}{d}\\\\

where,

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y = \frac{(4.8\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

<u>y = 2.4 x 10⁻³ m = 0.24 cm</u>

<u></u>

a) FOR λ = 640 nm = 6.4 x 10⁻⁷ m:

y = \frac{(6.4\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

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3 years ago
Could I please get some help on this question I don’t understand .
Oksana_A [137]

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

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The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

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Take the square root of both side

v = √156.8

v = 12.5 m/s

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Bonsoir pouvez vous m'aider svp.<br>Mathématiques
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bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci

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Answer:

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