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AlexFokin [52]
3 years ago
7

Conservation equations are powerful equations, because of how versatile and flexible they are to different physical situations.

Conservation of mass is a simple one that can even be applied to fluids with care. The conservation of momentum also applies to any closed system, such as collisions. We've examined the nuances of energy conservation in our labs with total mechanical energy. Does kinetic energy remain conserved in all collisions too?
a) true
b) false
Physics
1 answer:
Temka [501]3 years ago
8 0

Answer:

b) false

Explanation:

Since in the given situation it is mentioned that the mass conversation would be simple and same applied to the fluids with care also the conservation of momentum would be applied to any type of closed system like collisions

But as we know that

In the inelastic collisions, the total kinetic energy would not be remain conserved

So the given statement is false

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A major-league pitcher can throw a baseball in excess of 41.0 m/s. If a ball is thrown horizontally at this speed, how much will
SSSSS [86.1K]

Answer:

Ball will drop by 0.82 meter.

Explanation:

Horizontal speed = 41 m/s

Horizontal displacement = 17 m

Horizontal acceleration = 0 m/s²

Substituting in s = ut + 0.5at²

    17 = 41 t + 0.5 x 0 x t²

     t = 0.41 s

Now we need to find how much vertical distance ball travels in 0.41 s.

Initial vertical speed = 0 m/s

Time = 0.41s

Vertical acceleration = 9.81 m/s²

Substituting in s = ut + 0.5at²

    s = 0 x 0.41 + 0.5 x 9.81 x 0.41²

    s = 0.82 m

So ball will drop by 0.82 meter.

5 0
2 years ago
An unknown gas effuses 2.165 times faster than xe. what is the molar mass of the gas? show the set up and answer with unit.
lyudmila [28]

The unknown gas has a molar mass of 27.94 g/mol.

<h3>Steps</h3>

Use Graham's Law, which states that the rate of effusion of a gas is proportional to its molar mass squared.

Two different gases, (a) and (b), are compared in the following equation, which expresses this:

(R(a)/R(b)^2 = M(b)/M (a)

The effusion rate is R.

M, the molar mass

If gas (a) is the unknown gas and Xe(M = 131 g/mol) is the second gas, then the answer to your question is:

Square both sides, and you get:

(2.165)² = 131 g/mol/ M (a)

M(a)(2.165)² = 131

M(a) is equal to 131/(2.165)² = 27.94 g/mol.

Thus, the unknown gas has a molar mass of 27.94 g/mol.

<h3>How is molar mass determined?</h3>

Divide each element's atomic weight (found in the periodic table) by the quantity of that element's atoms in the compound. Add up the totals, and then follow the number with the units of grams/mole.

Learn more about Graham's law of effusion here brainly.com/question/22359712

#SPJ4

6 0
2 years ago
A ball is thrown straight up with a launch of 3 m/s.
PtichkaEL [24]

Explanation:

The ball is in free fall (gravity is the only force acting on the ball), so its acceleration is 9.8 m/s² down during the entire path.

7 0
3 years ago
20-kilogram canoe is floating downriver at 2 m/s. what’s the kinetic energy?
ziro4ka [17]

Answer:

40J

Explanation:

Kinetic energy = 1/2 mv^2

Where m = mass and

v = velocity

Given mass = 20kg

v = 2m/s

K.E = 1/2 x 20 x2^2

= 1/2 x 20 x 2 x 2

= 80/2

= 40J

6 0
3 years ago
Read 2 more answers
A piston in an internal combustion engine applies torque during 150° of each full rotation of the crankshaft to which it is conn
aalyn [17]

Answer:

T=1.566 N.m

Explanation:

Given that:

rotational speed of the scrank shaft, N = 2500 rpm

power produced by one cylinder, P = 410 W

We know, in case of rotational power:

P=\frac{2\pi.N.T}{60}

where: T= torque

Substituting the respective values in the above eq.

410=\frac{2\pi\times2500\times T}{60}

T= \frac{410\times60}{2\pi\times2500}

T=1.566 N.m is the torque applied by the each piston of the engine.

4 0
2 years ago
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