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almond37 [142]
3 years ago
6

HELP ASAP!!! So stressed! :(

Physics
1 answer:
nasty-shy [4]3 years ago
7 0
Question #16:. last choice.
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Answer:

E = 31.329 N/C.

Explanation:

The differential electric field dE at the center of curvature of the arc is

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E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta  }{r^2} cos(\theta)

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.

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Therefore,

E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.

evaluating the integral, and putting in the numerical values  we get:

E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\

\boxed{ E = 31.329N/C.}

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