Answer:
B = 5.59x10⁹ T
Explanation:
The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:
<u>We have:</u>
F = 1.4x10⁻³ N
v = 2.6x10⁶ m/s
θ = 37.0°
q = 2*p = 2*1.6x10⁻¹⁹ C
Hence, the strength of the magnetic field is:

Therefore, the strength of the magnetic field is 5.59x10⁹ T.
I hope it helps you!
Answer:
Check the correctness of the relation c=1 √μ0∈0 where the symbols have their usual meaning. check-circle.
Explanation:
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I think the answer is "<span>The ball that went out of the park shows more work because the distance was greater."</span>