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Ray Of Light [21]
2 years ago
9

Please help.......

Physics
1 answer:
IceJOKER [234]2 years ago
3 0

Answer:

(L: Length, T: Time)

p: Dimension: L; unit: m

q: Dimension: L/T or (L)*(T)^-1; unit: m/s

r: Dimension: L/T^2 or (L)*(T)^-2; unit: m/s^2

Explanation:

since y is distance (Length), make all terms L distance.

p is same as y dimension ==> dimension: L; unit: m (meter)

qt dimension is L ==>  q dimension :L/T; unit: m/s

rt^2 dimension is L ==> r dimension : L/T^2; unit: m/s^2

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The density of mercury is 13.6 g/ml. what is its density in lbs/L
solong [7]

Answer:

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Explanation:

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4 0
3 years ago
Constants A capacitor is connected across an ac source that has voltage amplitude 59 0 V and frequency 77 0 Hz Part C What is th
Vladimir79 [104]

Answer:

C = 1.77 \times 10^{-4} F

Explanation:

As we know that in AC circuit we have

V = i x_c

here we have

V = 59 V

i = 5.05 A

so we will have

x_c = \frac{59}{5.05}

x_c = 11.68 ohm

also we know that

x_c = \frac{1}{\omega C}

here we will have

11.68 = \frac{1}{(2\pi 77)C}

C = 1.77 \times 10^{-4} F

7 0
3 years ago
Which type of galaxy is too small for gravity to form it into an easily describable shape?
oksano4ka [1.4K]
If you think about it, irregular galaxies dont really have a describable shape, as you can tell by the name. So B. 
6 0
3 years ago
Read 2 more answers
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
ra1l [238]

Answer:

a) t = 4.16 s

b) x = 141.51 m

Explanation:

Given

v = 21.5 m/s

x0 = 52.0 m

a = 6.0 m/s²

a) Motorcycle

x = v0*t + (a*t²/2)

x = 21.5t + (6*t²/2)

x = 21.5t + 3t²   <em>(I)</em>

Car

x = x0 + v0*t

x = 52 + 21.5t  <em>(II)</em>

<em />

then we can apply <em>I = II</em>

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

⇒ t = 4.16 s

b) We can use <em>I</em> or <em>II</em>, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

8 0
3 years ago
Show the weight of the ladder and draw the missing Frictional force.
madreJ [45]
Since there is no friction between the ladder and the wall, there can be no vertical force component. That's the tricky part ;)

So to find the weight, divide the 100N <em>normal</em> force by earths gravitational acceleration, 9.8m/s^2

W =  \frac{N}{g}  =  \frac{100N}{9.8m/s^{2}} =  \frac{100}{9.8} = 10.2kg


Then;
Draw an arrow at the base of the ladder pointing towards the wall with a value of 30N, to show the frictional force.
5 0
3 years ago
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