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laila [671]
3 years ago
11

A parallel circuit has a total current of 4 Amperes and an equivalent resistance of .5 Ohms. What is the power in this circuit?

Physics
2 answers:
tiny-mole [99]3 years ago
5 0

Answer:

=8.0 Watts

Explanation:

Power is a ratio of work done over time. The power in an electric circuit is calculated using the following formula:

P=I²R

P is power, I is  current, R is resistance

Therefore,  Power= 4²ₓ 0.5Ω

=8.0 Watts

liubo4ka [24]3 years ago
3 0

The power in the parallel circuit is 8 W.

<u>Explanation: </u>

Power in an electric circuit is defined as the current generated for a given amount of input voltage. So power of an electric circuit is directly proportional to the product of current and voltage in the circuit. The mathematical representation is

             \text { Power }=\text { Current } \times \text { voltage }

As per Ohm’s law, the current flowing in a closed circuit is directly proportional to the voltage applied to the circuit and resistance is the constant of proportionality between them. So

            \text { Current } \propto \text { voltage }

            \text {Voltage}=\text {Current} \times \text {Resistance}

Thus the formula for power in terms of resistance will look like

      \text { Power }=\text { Current } \times \text { current } \times \text { resistance }=(\text { Current })^{2} \times \text { Resistance }

As it is given that the net current in the parallel circuit is 4 A and equivalent resistance of the parallel circuit is given as 0.5 ohms. Then power is

                 \text { Power }=4 \times 4 \times 0.5 = 8 W

Thus, the power in the parallel circuit is 8 W.

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Yes, these two objects have different masses.

<h3>How can we calculate that this statement is right ?</h3>

To calculate the precision of mass we are using the formula,

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For the first case we are given,

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For the first case \trianglem is 25.47 Kg..

For the second case we are given,

m₁= The recorded value of mass

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P= Precision of the mass

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So, according to the formula, \trianglem will be,

\trianglem= \frac{0.13}{0.005}-0.13

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For the second case \trianglem is 25.87 Kg.

For the two cases  \trianglem has different values, 25.47 Kg≠25.87 Kg.

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A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object i
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(a)  If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)  if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}

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when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)

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