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Alika [10]
3 years ago
6

Will give brainliest to best answer.

Chemistry
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

2. Write balanced nuclear equations for the following situations. For each, be sure to show the parent element, the daughter element, and any particles emitted. For each element, use notation that includes atomic mass and atomic number. (12 points)

a. Actinium-225 decays by alpha decay. (3 points)

225 - 4 = 221, 89 - 2 = 87,  

" 225/89 Ac = 221/87 Fr + 4/2 a "

b. Helium-6 decays by beta decay. (3 points)

neutron=  4-1=3 proton= 2+1=3

" 6/2 He = 6/3 Li + 0/-1 β "

c. Barium-141 and krypton-92 are produced by the bombardment of uranium-235 with a neutron. Complete the reaction:(3 points)

235/92 Ur + 1/0 n = 141/56 Ba + 92/36 Kr ?

d. Deuterium and tritium fuse to form helium-4. (3 points)

2/1 H + 3/1H = 4/2 He + 1/0 n

Explanation:

a p e x, and btw the deuterium and tritium are isotopes of hydrogen, your welcome :)

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5.77 g of nitrogen react with excess hydrogen producing 6.83 g of ammonia what is the percent yield. Determine/Label the actual
nata0808 [166]

Answer:

Percentage yield is 41.21%

Explanation:

Equation of reaction,

N₂ + 3H₂ → 2NH₃

Actual NH3 = 6.83g

Mass of N2 = 5.77g

Theoretical yield = ?

5.77g of N2 = 6.83g of NH3

14g of N2 = xg

X = (14 × 6.83) / 5.77

X = 95.62 / 5.77

X = 16.57g of NH3

Theoretical yield of NH3 is 16.57g

Percentage yield = (actual yield / theoretical yield) × 100

% yield = (6.83 / 16.57) × 100

% yield = 0.4121 × 100

% yield = 41.21%

The percentage yield of NH3 is 41.21%

6 0
3 years ago
A 1.513 g sample of KHP (C8H5O4K) is dissolved in 50.0 mL of DI water. When the KHP solution was titrated with NaOH, 14.8 mL was
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Answer:

0.501 M

Explanation:

  • KHP + NaOH → NaKP + H₂O

First we <u>convert 1.513 g of KHP into moles</u>, using its <em>molar mass</em>:

  • 1.513 g ÷ 204.22 g/mol = 7.41x10⁻³ mol = 7.41 mmol

As <em>1 mol of KHP reacts with 1 mol of NaOH</em>, in 14.8 mL of the NaOH solution there were 7.41 mmoles of NaOH.

With the above information in mind we can <u>calculate the molarity of the NaOH solution</u>:

  • 7.41 mmol / 14.8 mL = 0.501 M
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