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xxTIMURxx [149]
3 years ago
12

A piston-cylinder apparatus has a piston of mass 2kg and diameterof

Engineering
1 answer:
iragen [17]3 years ago
6 0

Answer:

M =2.33 kg

Explanation:

given data:

mass of piston - 2kg

diameter of piston is 10 cm

height of water 30 cm

atmospheric pressure 101 kPa

water temperature = 50°C

Density of water at 50 degree celcius is 988kg/m^3

volume of cylinder is  V = A \times h

                                       = \pi r^2 \times h

                                       = \pi 0.05^2\times 0.3

mass of available in the given container is

M = V\times d

  = volume \times density

= \pi 0.05^2\times 0.3 \times 988

M =2.33 kg

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Elanso [62]

To solve this problem it is necessary to apply the concepts related to density in relation to mass and volume for each of the states presented.

Density can be defined as

\rho = \frac{m}{V}

Where

m = Mass

V = Volume

For state one we know that

\rho_1 = \frac{m_1}{V}

m_1 = \rho_1 V

m_1 = 1.18*1

m_1 = 1.18Kg

For state two we have to

\rho_2 = \frac{m_2}{V}

m_2 = \rho_2 V

m_1 = 7.2*1

m_1 = 7.2Kg

Therefore the total change of mass would be

\Delta m = m_2-m_1

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\Delta m = 6.02Kg

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5 0
2 years ago
A gas tank is known to have a thickness of 0.5 inches and an internal pressure of 2.2 ksi. Assuming that the maximum allowable s
sergiy2304 [10]

Answer:

D_o=11.9inch

Explanation:

From the question we are told that:

Thickness T=0.5

Internal PressureP=2.2Ksi

Shear stress \sigma=12ksi

Elastic modulus \gamma= 35000

Generally the equation for shear stress is mathematically given by

 \sigma=\frac{P*r_1}{2*t}

Where

r_i=internal Radius

Therefore

 12=\frac{2.2*r_1}{2*0.5}

 r_i=5.45

Generally

 r_o=r_1+t

 r_o=5.45+0.5

 r_o=5.95

Generally the equation for outer diameter is mathematically given by

 D_o=2r_o

 D_o=11.9inch

Therefore

Assuming that the thin cylinder is subjected to integral Pressure

Outer Diameter is

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7 0
3 years ago
Decide whether the function is an exponential growth or exponential decay function, and find the constant percentage rate of gro
sasho [114]

Answer:

Just answered this to confirm my profile.

Explanation:

I dont have a clue, this is just to confirm my profile.

8 0
3 years ago
A smelter emits SO2 at a rate of 10,000 kg/day. The stack is 200 m tall and the plume rise is 100 m. The windspeed is 2 m/s at a
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Answer:

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3 years ago
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