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Semenov [28]
3 years ago
5

This is for today someone can help me pls

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

m= 90, I couldn't figure out n

Step-by-step explanation:

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6m^2 + 7n<br>Identify the constant, variable, and terms​
Leokris [45]
<h3>Answer:</h3>

<u>Given equation</u> :- 6m² + 7n

where,

  • <u>Constant</u> = 0.
  • <u>Variable</u> = m, n.
  • <u>Terms</u> = 6m² , 7n.
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If you want to obtain a Class E license before you turn 18, you must______.
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Sally ate 1/6 of a fruit pie and gave 1/5 of the remainder to her sister. What fraction of fruit pie did she give away? hURYY
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Milan puts 1/4 of her lawn-mowing money in savings and uses 1/2 of the remaining money to pay back her sister. If she has $15 left

Step-by-step explanation:

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X=2t/t^2 +1 and y=2t/t^2 +1 <br>Find dy/dx​
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3 years ago
A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor
Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 700, \sigma = 50.

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

Z = \frac{X - \mu}{\sigma}

Z = \frac{790 - 700}{50}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

Z = \frac{X - \mu}{\sigma}

Z = \frac{575 - 700}{50}

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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