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3 years ago

How to do 3 and 4 questions

Chemistry

1 answer:

Kipish [7]3 years ago

5 0

Answer:

3) Q = -836.8 J.

4) Q = 950J.

Explanation:

Hello there!

In this case, for those calorimetry problems, we use the general equation:

$Q=mC\Delta T$

Thus, we proceed as follows:

3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:

$Q=(5g)(4.184\frac{J}{g\°C} )(40\°C-80\°C)\\\\Q=-836.8J$

4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:

$Q=(5g)(1.90\frac{J}{g\°C} )(200\°C-100\°C)\\\\Q=950J$

Regards!

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Answer:

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Explanation:

Excited state configuration: 1s² 2s² 2p² 3s¹

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Solution:

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A ground state configuration shows the lowest allowed energy levels of an atom. The excited state denotes when electrons have moved to higher energy levels away from their ground state.

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