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marysya [2.9K]
3 years ago
7

0.225L solution of H2CO3 is neutralized by 0.0880L of a 1.22 M Fe(OH)3 solution. What

Chemistry
1 answer:
ikadub [295]3 years ago
6 0

Answer:

0.716

Explanation:

First, write the balanced equation:

3 H2CO3 + 2 Fe(OH)3 ----> Fe2(CO3)3 + 6 H2O

Second, go from the molarity of H2CO3 to liters of Fe(OH)3

(Pull mole ratio from balanced equation)

1.22/1L  x  0.0880/1  x  3molH2CO3/2molFe(OH)3 x 1/0.225L

Use calculator, and you end up with 0.7157333

Round to 0.716

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Answer:

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Explanation:

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<u>To solve this problem we need to use PV=nRT</u>, so first let's convert the given units:

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We need to calculate V, so in order to do that we calculate n, using the mass of the reactant (P₄S₃):

0.576 g P₄S₃ * \frac{1molP_{4}S_{3}}{220gP_{4}S_{3}} *\frac{3molSO_{2}}{1molP_{4}S_{3}} = 7.85 * 10⁻³ mol SO₂ = n

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0.983 atm * V =  7.85 * 10⁻³ mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.95 K

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0.1946 * 1000 = 194.6 mL

8 0
3 years ago
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sattari [20]

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Answer:

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