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2 years ago

0.225L solution of H2CO3 is neutralized by 0.0880L of a 1.22 M Fe(OH)3 solution. What

Chemistry

1 answer:

ikadub [295]2 years ago

6 0

Answer:

0.716

Explanation:

First, write the balanced equation:

3 H2CO3 + 2 Fe(OH)3 ----> Fe2(CO3)3 + 6 H2O

Second, go from the molarity of H2CO3 to liters of Fe(OH)3

(Pull mole ratio from balanced equation)

1.22/1L x 0.0880/1 x 3molH2CO3/2molFe(OH)3 x 1/0.225L

Use calculator, and you end up with 0.7157333

Round to 0.716

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