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geniusboy [140]
3 years ago
8

In the figure, XYZ=MNL Find m

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

m = 33°

Step-by-step explanation:

x = 33°

from picture ;

x = m = 33°

n = y = 124

You might be interested in
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Neil drives at an average speed of 60 miles/hour to reach his destination 480 miles away. On the way back, he decides to increas
daser333 [38]

Answer:

  480/(x+60) ≤ 7

Step-by-step explanation:

We can use the relations ...

  time = distance/speed

  distance = speed×time

  speed = distance/time

to write the required inequality any of several ways.

Since the problem is posed in terms of time (7 hours) and an increase in speed (x), we can write the time inequality as ...

  480/(60+x) ≤ 7

Multiplying this by the denominator gives us a distance inequality:

  7(60+x) ≥ 480 . . . . . . at his desired speed, Neil will go no less than 480 miles in 7 hours

Or, we can write an inequality for the increase in speed directly:

  480/7 -60 ≤ x . . . . . . x is at least the difference between the speed of 480 miles in 7 hours and the speed of 60 miles per hour

___

Any of the above inequalities will give the desired value of x.

4 0
3 years ago
3,480
Serjik [45]

Answer

B

explanation

3480ones = 3480x1=3480

8 0
1 year ago
Can u please help me please. Please
jonny [76]
The answer is
C = 4 ÷ 1/5
6 0
3 years ago
What is the domain of this exponential function? y=2x
trasher [3.6K]

Answer:

x∈R

Step-by-step explanation:

y=2^{x}

2>0

The domain is all real numbers.

x∈R

8 0
3 years ago
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