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blondinia [14]
3 years ago
5

point m is located at negative 6,5 and point n is located at 7,5. what is the distance, in units, between point m and point n?

Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

1

Step-by-step explanation:

the y axis is the same the x axis is different by  1. because 7-6= 1

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When I add a number to another number four times as big, the result is 30. find the first number
Alex73 [517]

Answer:

x = 6

Step-by-step explanation:

Let x = first number

x+4x = 30

5x = 30

Divide by 5

5x/5 =30/5

x = 6

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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n > 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

4 0
2 years ago
X <br> 2<br> +(y−7.5) <br> 2<br> = <br> 49<br> 9<br> ​ What is the radius?
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50 is the answer hugnfgh

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Ms. Federman graded 5 papers in 40 minutes. At this rate, how many minutes will it take her to grade 30 papers?
Ksivusya [100]

Answer:

240 minutes

Step-by-step explanation:

If it's 40 minutes for just 5 papers, we need to figure how many minutes it would take to grade just 1. So you have to divide 40 by 5 which is 8. Then 8 time 30 which is 240.

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Here, we are required to write a real-world problem that can be represented by the given equation

On the left hand side of the equation, we can say that :

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Ultimately, the real-world problem may be in the form :

Six added to Twice my cousin's age is equal to 4 added to thrice his age.

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