Answer: D. Regulate the thalamus
Explanation:
Answer:The mother's antibodies can destroy the red blood cells of the fetus.
Explanation:
If a woman with an Rh negative (Rh-) blood group has a child with an Rh positive (Rh +) male, there is a possibility that the child is also Rh +. Although this has no consequences throughout pregnancy itself, as the mother's and fetus's blood does not come into direct contact during pregnancy, it can have serious consequences for subsequent pregnancies.
In fact, rupture of the placenta at the time of childbirth may allow some red blood cells from the fetus to pass into the maternal circulation and cause sensitization, meaning the woman's body will detect them and begin to make anti-human antibodies. Rh that will persist indefinitely in the blood. If a woman regenerates another Rh + child, the anti-Rh antibodies present in her blood will pass easily into the fetus's blood through the placenta and attack and destroy the fetus' red blood cells, which can lead to severe fetal anemia and serious repercussions that sometimes lead to intrauterine death.
For giving you understanding ; we need Free O2 but Oxygen is also available in H20 right why dont we use it !!
As the early atmosphere was reducing as there was no free oxygen but it was later produced by chemoautotrophic bacteria !! Living thing release O2 in atmosphere thus making it oxidising in nature and then life evolves !!
Answer:
the gene for yellow body and the gene for forked bristles
Explanation:
The two genes that will have the highest recombination frequency are the gene for yellow body and the gene for forked bristles.
<em>Gene recombination refers to the exchange of genetic materials between different gene-containing regions (loci) on the same chromosome or between two or more independent chromosomes. A linkage map shows the frequency of recombination between genes.</em>
Generally, on a linkage map, when two loci are close to one another on the same chromosome, the frequency of recombination of the genes would be less than that of two loci that are further apart. In other words, the closer the loci, the lower the frequency of gene recombination and vice versa.
<em>In this case, the distance between the genes for yellow body and tan body is 27.5 map units, yellow body and sable body is 43 map units, yellow body and forked bristles is 56.7 map units. </em><u><em>The genes for yellow and forked bristles are the furthest to each other with 66.7 map units and, as such, will have the highest recombination frequency. </em></u>
Answer: Exaptations
Explanation:
Exaptation explains a shift in the function of a trait during evolution. For example, a trait can evolve because it is used for one particular function, but eventually it may come to be used foranother function. Exaptations are found both in anatomy and behaviour. A classic example are bird feathers: at first they may have evolved for temperature regulation, but subsequently were adapted for flight. Exaptation was said to proposed by Stephen Jay Gould and Elisabeth Vrba as a substitute for what they considered to be a teleologically loaded term 'pre-adaptation'.[
