If markup is 60% of the cost, you have
... markup = 0.60×cost
... markup/0.60 = cost
... $207.20/0.60 = cost = $345.33
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If markup is 60% of the selling price, the other 40% is the cost. So, the cost is 40/60 = 2/3 of the markup.
... cost = (2/3)×markup = (2/3)×$207.20
... cost = $138.13
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Markup can be specified in terms of either selling price or cost. Those are the usual reference values; there could be others. When only the percentage is given, you don't have enough information to work the problem. You need to know what it is a percentage of. (Example problems in your text may tell you the expected interpretation.)
Solve: 2y(6 - 1)(6 - 1) = - 200
Simplify both sides of the equation:
50y = - 200
Divide both sides by 50
50y/50 = -200/50
y = - 4
Answer: y = - 4
Hope that helps!!!!!!! (Answer: y = - 4)
Answer:
First one: x = 3, and y = 2
Second: 5
Third: Yes because he will have $37.50
Fourth: The numbers 2.5 and 3 will make it true
Step-by-step explanation:
1. 4(3) + 2(2) + 3 = 12 + 4 + 3 = 19
2. 4x + 2 = 22, 4x = 20, x = 5
3. 2.25y + 7.25z + 11.25, 2.25(2) + 7.25(3) + 11.25 = 4.5 + 21.75 + 11.25 = 37.5
He will get $37.50, which is enough.
4. The numbers 2.5 and 3 will make it true: 2(2.5) + 3 = 5 + 3 = 8, 2(3) + 3 = 6 + 3 = 9, the numbers below it won't make it true.
Answer:
yes
Step-by-step explanation:
There are several ways to go at this.
My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.
Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.
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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.
(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0
The value of h(5) is zero, so x-5 is a factor of h(x).
