Its multiple choice pls help

kompoz [17]

3x - 7 + 7 = 12 + 7
3x = 19
3x/3 = 19/3
X = 19/3 = 6 1/3

8 0

2 years ago

Leah has The flowers shown she wants to put them in 4 vases with the same number in each case how many flowers does she need to

dsp73

Answer:

The solution is obtained by dividing the number of flowers by the number of vases.

Step-by-step explanation:

The story problem is very straightforward. Normally, you need to read the problem and understand it.

Let's look at the question again.

Although we do not have all the quantities, we can still show how to solve the problem.

Let x be the total number of flowers.

There are 4 vases.

Therefore, the number of flowers in each vase will be:

x/4

Flow the same rule for similar problems.

5 0

2 years ago

5p coins weigh approximately 3 grams.

Elza [17]

Answer: 0.3 kg

Step-by-step explanation:

£5 = 500p

500p ÷ 5 = 100

100 x 3 = 300 grams

300 ÷ 1000 = 0.3 kg

Hope this helps :)

3 0

3 years ago

Read 2 more answers

Lester makes a string of beads 17 inches long. Jill makes a string of beads that is 3 inches longer than Lester’s. They put thei

Komok [63]

Lester-17
Jill-17+3=20
Together 17+20=37 inches.

6 0

3 years ago

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

2 years ago