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2 years ago

Its multiple choice pls help

Mathematics

1 answer:

V125BC [204]2 years ago

3 0

Answer:

I don't understand the question could u explain it more?

Step-by-step explanation:

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Does anyone know the answer what to add and multiply because I really don't get it

Sindrei [870]

3205 that’s the answer

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3 years ago

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A survey handed out to individuals at a major shopping mall in a small Florida city in July asked the following: Gender Age Ethn

AysviL [449]

Answer and Explanation:

Gender data is categorical as it can be sorted into two categories - males and females - and does not involve any numerical values.

Age data is ratio as each person's age is a numerical value and it has a natural zero as point of origin. Moreover, the numerical values cannot be negative.

Ethnicity data is categorical as the various ethnicities to which those surveyed can belong are separate categories. There are no numerical values involved.

Length of residency data is ratio as the length duration is measured in number of years, thus having a numerical value. There is also a natural zero as point of origin and no possible negative values.

Overall satisfaction with city services data is ordinal as it is based on a ranking from poor to excellent.

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4 0

2 years ago

Helppppp fast pleaseeeeeee

mario62 [17]

Answer:

Step-by-step explanation:

68 69 71 71 71 73 74 75 75 78 and then cross off each number until you reach the middle. You will see 71 and 73 next to each other, what's in-between those two numbers? 72!

7 0

3 years ago

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

3 years ago

Show me the work for 400-126

swat32

400-126=274

400
126
-----
0-6 can't go into so make the 0 a 6
Then make 0-2 make 0 a 10 then a 9
Then make 4 into a 3

4 0

3 years ago