Answer:
pH = 11.216.
Explanation:
Hello there!
In this case, according to the ionization of ammonia in aqueous solution:
We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:
![Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BNH_4%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BNH_3%5D%7D%20%5C%5C%5C%5C1.80x10%5E%7B-5%7D%3D%5Cfrac%7Bx%2Ax%7D%7B0.150-x%7D)
However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:
Which is also:
![[OH^-]=1.643x10^{-3}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.643x10%5E%7B-3%7DM)
Thereafter we can compute the pOH first:
Finally, the pH turns out:
Regards!
Answer:
C
Explanation:
garbage being reduced is a far more long term other than the other stupid answer choices
The choices can be found elsewhere and as follows:
<span>A.The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice.. .
B.The enzyme pectinase enhances the taste of fruit juices, making them more popular.. .
C.The enzyme pectinase speeds up the breakdown of toxins in fruits, producing more juice.
The correct answer would be A. </span>The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice. With this, the manufacturer company will get more volume of product from same amount of resource.
Answer:
41.44 g
Explanation:
First of all, we must put down the equation of the reaction;
Number of moles of CaO = 33g/56 g/mol = 0.59 moles
Number of moles of H20 = 10g/18 g/mol = 0.56 moles
Since the reaction is in 1:1 mole ration, H2O is the limiting reactant
Hence;
mass of Ca(OH)2 produced = 0.56 moles * 74 g/mol = 41.44 g
