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3 years ago

I NEED HELP WITH CHEM PLEASE HAVE A DECENT ANSWER

Chemistry

1 answer:

anastassius [24]3 years ago

8 0

Answer:

x is HCl because pH = 2 (acid and it reacted with Mg plus it turned litmus paper to red)

y is NaOH because pH = 10 (base and turned litmus paper to blue)

z is NaCl because pH = 7 (neutral and no reaction to litmus paper and Mg)

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Olegator [25]

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3 years ago

Explain difference in appearance between a pure substance and a mixture.

Nata [24]

A pure substance is a substance which cannot be separated physically or chemically. It is the same wherever found on earth. For example, pure gold is a pure substance. It will be the same whether it is found where you live or on another country. A mixture can be either homogeneous or heterogeneous. A homogeneous mixture is a mixture that looks the same throughout but is made of more than one element. An example of this would be salt and water mixture. A heterogeneous mixture is a mixture in which you can easily identify the different parts which make it up. An example of this would be pizza. Both these mixtures can be broken into different parts either physically or chemically.

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3 years ago

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In another universe the electrons are described by four quantum numbers p, q, r, and s. The rules for these quantum numbers are

andreyandreev [35.5K]

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3 years ago

What element has 2 occupied principals of energy levels

DerKrebs [107]

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3 years ago

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Schach [20]

Answer:

The energy of a wave is inversely proportional to the wavelength of the wave.

As wavelength increases, the energy of the wave decreases.

As wavelength decreases, the energy of the wave increases.

Explanation:

The energy of a wave is directly proportional to the wave's frequency. As frequency increases, so does the energy of the wave.

$E\propto f$ (energy $E$ is proportional to frequency $f$ )

<u>How is this related to wavelength?</u>

Frequency is inversely proportional to wavelength. That means that as frequency increases, wavelength decreases and as frequency decreases, wavelength increases.

$f\propto \frac{1}{\lambda}$ (frequency $f$ is inversely proportional to wavelength $\lambda$ )

Therefore, as wavelength increases, the energy of a wave decreases and as wavelength decreases, the energy of a wave increases.

$E\propto f\propto \frac{1}{\lambda}$

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3 years ago