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Zanzabum
3 years ago
9

Given the figure below, find the values of x and z. (8x – 20) (14x – 20)

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

Problem #1:  x = 2.5

Problem #2:  x = 10/7

Step-by-step explanation:

Step 1:  Find the value of x in (8x - 20)

8x - 20 = 0

<u>Add 20 to both sides</u>

8x - 20 + 20 = 0 + 20

<em>8x = 20</em>

<em />

<u>Divide both sides by 8</u>

8x / 8 = 20 / 8

<em>x = 2.5</em>

<em />

Answer:  x = 2.5

<em />

Step 2:  Find the value of x in (14x - 20)

14x - 20 = 0

<u>Add 20 to both sides</u>

14x - 20 + 20 = 0 + 20

<em>14x = 20</em>

<em />

<u>Divide both sides by 14</u>

14x / 14 = 20 / 14

<em>x = 10/7</em>

<em />

Answer:  x = 10/7

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Answer:

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We can see on the graph of g(x) that y-intercept is (0, 2)

The table doesn't have the value for x = 0 but we can observe that it is exponential function and has the formula:

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<u>We can find its y-intercept:</u>

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<u>We can compare and see that:</u>

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====

Note: If only the values in the table considered, then correct option is D.

3 0
3 years ago
Given the domain {-4, 0, 5}, what is the range for the relation 12x + 6y = 24?A.{12, 4, -6}B.{-4, 4, 14}C.{2, 4, 9}D.{-12, -4, 6
Leokris [45]

Answer:

{12, 4, -6}

Step-by-step explanation:

The relation is given by the equation as 12x + 6y = 24 ........... (1)

Now, the domain of this function is {-4, 0, 5}

We have to find the range of this function corresponding to the given domain.

Now, for x = - 4,  

12(-4) + 6y = 24 {From equation (1)}

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⇒ 6y = 24

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12(5) + 6y = 24 {From equation (1)}

⇒ 6y = -36

⇒ y = -6

Hence, the range for the relation is {12, 4, -6} (Answer)

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