an = a1r^(n-1)
a5 = a1 r^(5-1)
-6 =a1 r^4
a2 = a1 r^(2-1)
-48 = a1 r
divide
-6 =a1 r^4
---------------- yields 1/8 = r^3 take the cube root or each side
-48 = a1 r 1/2 = r
an = a1r^(n-1)
an = a1 (1/2)^ (n-1)
-48 = a1 (1/2) ^1
divide by 1/2
-96 = a1
an = -96 (1/2)^ (n-1)
the sum
Sn = a1[(r^n - 1/(r - 1)]
S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]
=-96 [ (1/2) ^ 17 -1 /-1/2]
= 192 * [-131071/131072]
approximately -192
$450/week
30.5 hours/week
450/30.5 = $14.75
The answer is A (14.75/hour).
The range of the data set is 12.
Answer:
1. 8/3
2. 1/7
3. 1/12
4. 1/27
Step-by-step explanation:
1. 3/8 * m = 1
Multiply by 8/3
8/3 * 3/8 m = 1* 8/3
m = 8/3
2. 7 * m = 1
Divide by 7
7*m /7 = 1/7
m = 1/7
3. 3 ÷m = 36
Multiply by m
3 ÷m * m = 36*m
3 = 36*m
Divide by 36
3/36 = 36*m/26
1/12 = m
4. 4/9 ÷m = 12
Multiply by m
4/9 ÷m * m = 12*m
4/9 = 12*m
Multiply by 1/12
4/9 *1/12 = 12*m * 1/12
4/12 *1/9 = m
1/3*1/9 =m
1/27
BD is the same length as FD, so FD=14