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3 years ago

14

The lens system within a camera forms a _______ on the sensor. A. virtual, upright image B. real, inverted image C. r

eal, upright image D. virtual, inverted image

2 answers:

Rashid [163]3 years ago

7 0

B. The image on the film or sensor is real and inverted.

Lisa [10]3 years ago

5 0

The answer is virtual and inverted

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Infer which group you would expect to contain element 117. Use the periodic table to help you answer this question.

Gre4nikov [31]

Answer:

halogen group

Explanation:

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2 years ago

Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.

Tresset [83]

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

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3 years ago

Read 2 more answers

A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The

Serhud [2]

Answer:

$A = 2.43*10^{-3} m$

Explanation:

power through string can be determined as shown in figure

$P = 2\pi ^2 HVA^2F^2$

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

$V = f *\lambda$ $\lambda = \frac{v}{f}$

therefore $P = 2\pi ^2 HVA^2(\frac{v}{f})^2$

$57.3 = \frac{2\pi ^2 * 0.567 *13.87^{3}* A^2}{(5.54*10^{-2})^2}$

$A = 2.43*10^{-3} m$

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3 years ago

The Hertzsprung-Russel diagram is used to show the relationship between which two characteristics of stars?

andre [41]

The Hertzsprung- Russel diagram is used to how the relationship between the absolute magnitudes of stars and their effective temperatures.

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3 years ago

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What is sin for the given right triangle?

Rzqust [24]

Sin of a right triangle is opposite divided by hypotenuse
in this case, that is 5/8.6 = 0.581395349<span>
</span>
you can easily remember the trig functions with this acronym:
SOH-CAH-TOA

S: Sine
O: Opposite
H: Hypotenuse

C: Cosine
A: Adjacent
H: Hypotenuse

T: Tangent
O: Opposite
A: Adjacent

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3 years ago