Explanation:
Given
The enthalpy of formation of RbF (s) is –557.7kJ/mol
The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol
The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)
= -583.8 - (-557.7) kJ/mol
= -26.1 kJ/mol
The enthalpy is negative which means that the temperature will rise when RbF is dissolved.
It is kept constant
There is the answer if it helped
The reaction has had a heat that is enthalpy of -22 kJ/mol. The exothermic process has been signaled by the negative sign.
The amount of energy that the system absorbs or releases to create the products is described as the heat of reaction.
The source of the reaction's heat is
H is equal to 3(413 Kj/mol) + 358 Kj/mol + 467 Kj/mol + 1070 Kj/mol = 3134 Kj/mol.
H prod equals 3(413 kj/mol) plus 347 kj/mol plus 358 kj/mol plus 467 kj/mol plus 745 kj/mol, or 3156 kj/mol.
H=3134 kj/mol - 3156 kj/mol = -22 Kj/mol
Negative findings point to an exothermic response.
A chemical process known as an exothermic reaction releases energy in the form of heat or light.
Learn more about exothermic reaction here-
brainly.com/question/10373907
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