Explanation:
The given reaction equation is as follows.
+ ___
As there is release of one hydrogen which shows that mass number has increase by 1 on the product side.
Therefore, particle must be added in order to balance the given reaction equation.
Hence, the complete reaction equation will be as follows.
For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway is mathematically given as
Ea2=89.28JKoule/mol
<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>Generally, the equation for the rate constant is mathematically given as
K=Ae^{Ea1/Rt}
Therefore
Ea2=89286.083Joule/mol
In conclusion, the activation energy
Ea2=89.28JKoule/mol
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