Answer:
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Explanation:
Initially
3.0 atm 0
At equilibrium
(3.0-2p) p
Equilibrium partial pressure of 
p = 0.45 atm
The value of equilibrium constant wil be given by :
After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :
After adding 1.5 atm of 
:
(2.1+1.5) atm 0.45 atm
At second equilibrium:'
(3.6-2P) (0.45+P)
The expression of equilibrium can be written as:
Solving for P:
P = 0.37 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:
= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Helium give me a thanks or brainiest answer if this helps!
Answer: 1.875 moles
Explanation:
2 NaN3(s) → 2 Na(s) + 3 N2(g)
From the equation above, Sodium azide has a chemical formula of NaN3 while nitrogen gas has a chemical formula of N2.
Therefore, If on decomposition
2 moles of NaN3 produce 3 moles of N2
1.25 mol of NaN3 produce Z moles of N2
To get the value of Z, cross multiply
Z x 2 moles = 3 moles x 1.25 moles
2 moles•Z = 3.75 moles²
Divide both sides by 2 moles
2 moles•Z/2 moles = 3.75 moles²/2 moles
Z = 1.875 moles
Thus, 1.875 moles of N2 are produced by the decomposition of 1.25 mol of sodium azide
I've done this a few times and keep coming up with 5.0 L . I used the mole ratio, and SO 2 as the LR. That would make 2 moles of SO3 5.0 L but its not one of your choices. the temp and pressure are constant, so according to n/v = p/rt the volume is the same as the moles. hope this helps
Answer:
Thus the order of covalent character will be
DG < EG < DF < DE
Explanation:
The electronegativity decides the nature of bond formed between two atoms.
More the difference in electronegativity more the ionic character in the bond formed.
Let us check the electronegativity difference between the elements forming molecules
a) DE :
3.8-3.3 = 0.5
b) DG :
3.8-1.3 = 2.5
c) EG
3.3-1.3 = 2
d) DF
3.8-2.8 = 1.3
So the maximum ionic character will be in DG and minimum in DE
Thus the order of covalent character will be
DG < EG < DF < DE
