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Paul [167]
3 years ago
6

Where are the transition metals on the periodic table?

Chemistry
1 answer:
densk [106]3 years ago
3 0
D. In columns 3-12 in the centre of the table
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In a model of an atom, where would I find a valence electron<br><br><br> Help
Snowcat [4.5K]
The valence electron is the outermost shell
5 0
3 years ago
What is the molarity of a 0.250 L MgCl2 solution that contains 0.175 mol MgCl2?
spayn [35]

Explanation:

we know that 0.250 L = 0.250 dm3

molarity = concentration in dm3/ volume

molarity = 0.175/0.250 = 0.7 mol/dm3

4 0
3 years ago
Draw the structure of 4-methylcycloheptanol.
Furkat [3]

Answer:

<em>Answer is in the attachment</em>

6 0
3 years ago
It's 32°F (0°C) outside under normal atmospheric conditions (1 atm) at a stunt
Korolek [52]

The volume of the balloon is approximately 2652 liters.

<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (M), in kilograms per kilomole, and mass of the gas (m), in kilograms. The volume occupied by the gas (V), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}   (1)

Where:

  • R_{u} - Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
  • T - Temperature, in Kelvin
  • P - Pressure, in kilopascals

If we know that m = 0.239\,kg, R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}, T = 273.15\,K, P = 101.325\,kPa and M = 2.02\,\frac{kg}{kmol}, then the volume of the balloon is:

V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}

V = 2.652\,m^{3} (2652\,L)

The volume of the balloon is approximately 2652 liters. \blacksquare

To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877

4 0
2 years ago
What mass of radon is in 8.17 moles of radon?
Len [333]

Answer:

1813.74g

Explanation:

Given parameters:

Number of moles of radon  = 8.17moles

Unknown:

Mass of radon  = ?

Solution:

To solve this problem, we use the expression below:

      Number of moles = \frac{mass}{molar mass}  

Molar mass of radon  = 222g/mol

Now insert the parameters and solve;

    Mass of radon  = Number of moles x molar mass

                              = 8.17 x 222

                              = 1813.74g

4 0
3 years ago
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