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2 years ago

5

What does hydrochloric acid do

2 answers:

marta [7]2 years ago

6 0

Answer:

Hydrochloric acid (HCl) is commonly used for the neutralization of alkaline agents, as a bleaching agent, in food, textile, metal, and rubber industries. It is neutralized if released into the soil and it rapidly hydrolyzes when exposed to water. Skin exposure to low concentrations of hydrogen chloride gas or hydrochloric acid causes erythema and inflammation of the skin whereas high concentrations can cause severe chemical burns to the skin and mucous membranes.

Pepsi [2]2 years ago

6 0

Answer:

In food, textile, metal, and rubber industries, hydrochloric acid is widely used to neutralize alkaline substances and as a bleaching agent. When released into the soil, it is neutralized, and when exposed to water, it quickly hydrolyzes.

Hope this helps!

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Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I

Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

At t = 0 0.044M 0.044M 0.177M

At $t=t_{eq}$ (0.044-x)M (0.044-x)M (0.177+x)M

The expression for $K_c$ for the given reaction follows:

$K_c=\frac{[HI]^2}{[H_2]\times [I_2]}$

We are given:

$K_c=52$

Putting values in above equation, we get:

$52=\frac{(0.177+x)^2}{(0.044-x)^2}$

$x=0.0171M$

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0

2 years ago

The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A

Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

$-q_{combust} = q_{water} + q_{calori}$

$q_{combust}$ = heat of combustion of benzoic acid

$q_{water}$ = heat energy released to water

$q_{calori}$ = heat energy released to the calorimeter

Therefore,

$-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})$

1.056*26.42 = [0.987*4.18 + 6.66]( $T_{f}$ - 23.32)

27.8995 = [4.12566+6.660]( $T_{f}$ - 23.32)

( $T_{f}$ - 23.32) = 27.8995/10.7857 = 2.587

$T_{f}$ = 23.32 + 2.587 = 25.907°C

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navik [9.2K]

Protons, nuetrons, and electrons

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The correct answer is A) True

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sergejj [24]

Answer:

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