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KIM [24]
2 years ago
5

What does hydrochloric acid do

Chemistry
2 answers:
marta [7]2 years ago
6 0

Answer:

Hydrochloric acid (HCl) is commonly used for the neutralization of alkaline agents, as a bleaching agent, in food, textile, metal, and rubber industries. It is neutralized if released into the soil and it rapidly hydrolyzes when exposed to water. Skin exposure to low concentrations of hydrogen chloride gas or hydrochloric acid causes erythema and inflammation of the skin whereas high concentrations can cause severe chemical burns to the skin and mucous membranes.

Pepsi [2]2 years ago
6 0

Answer:

In food, textile, metal, and rubber industries, hydrochloric acid is widely used to neutralize alkaline substances and as a bleaching agent. When released into the soil, it is neutralized, and when exposed to water, it quickly hydrolyzes.

Hope this helps!

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Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
Consider these elements: p, ca, si, s, ga.<br> a. write the electron configuration for each element
dimulka [17.4K]
Method:

1) Find the atomic number in a periodic table: the number of electrons equal the atomic number

2) Use Aufbau rule

Element     atomic number       electron configuration
<span>
P                15                            1s2 2s2 2p6 3s2 3p3

Ca              20                            </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2

</span>Si                14</span><span>                            1s2 2s2 2p6 3s2 3p2

S                 16</span><span><span>                            1s2 2s2 2p6 3s2 3p4

</span>Ga               31.                   </span><span><span>        1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span>       </span>
7 0
3 years ago
How many grams of h20 are produced if 75g of CO2 are produced. (Work Shown with the answer would be preferred.)
Agata [3.3K]
2:7 ratio of ethane to O2 = 15:x 9solve for x)
x=52.5 mol O2
5 0
3 years ago
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
What is the reaction energy q of this reaction? use c2=931.5mev/u. express your answer in millions of electron volts to three si
Ann [662]
₉₂U²³⁵ + ₀n¹ → ₅₄Xe¹⁴⁰ + ₃₈Sr⁹⁴ + 2 ₀n¹
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Mass of products = 139.92144 + 93.91523 + 2* (1.008665) = 235.854000 amu
Mass defect Δ m = 236.052595 - 235.854000 = 0.198 amu
Reaction energy released Q = Δ m * 931.5
                                              = 0.198 * 931.5 = 185 MeV
5 0
3 years ago
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