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REY [17]
3 years ago
12

Bryce has selected a major in political science but has a little interest in understanding public relations

Physics
1 answer:
Dominik [7]3 years ago
8 0

Hi, you've asked an incomplete question. However, I assumed you want additional comments about this scenario.

<u>Explanation:</u>

Note, the term Major as used in academic contexts refers to a person's preferred interest or specialization at college or university.

Hence, the statement about Bryce appears to be contradictory, since we are told he "has little interest in understanding public relations".

You might be interested in
Una barra metálica de 2 m de largo recibe una fuerza que lo provoca una alargamiento o variación en su longitud de 0.3 cm ¿Cuál
Elan Coil [88]

Answer:

La deformación unitaria lineal experimentada por la barra es 1.5\times 10^{-3}.

Explanation:

De la Mecánica de Materiales sabemos que la deformación unitaria lineal es la razón de la variación de la longitud con respecto a su longitud inicial. Al asumirse que la variación longitudinal es muy pequeña con respecto a la longitud inicial, se puede utilizar la siguiente ecuación:

\epsilon = \frac{\Delta l}{l_{o}} (Eq. 1)

Donde:

\epsilon - Deformación unitaria, adimensional.

\Delta l - Cambio longitudinal, medido en metros.

l_{o} - Longitud inicial, medida en metros.

Si conocemos que \Delta l = 3\times 10^{-3}\,m y l_{o} = 2\,m, entonces la deformación unitaria lineal es:

\epsilon = \frac{3\times 10^{-3}\,m}{2\,m}

\epsilon = 1.5\times 10^{-3}

La deformación unitaria lineal experimentada por la barra es 1.5\times 10^{-3}.

3 0
4 years ago
What is one advantage of doing a field experiment instead of a laboratory experiment
harkovskaia [24]
Higher ecological validity
5 0
3 years ago
The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,
kupik [55]

Answer:

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

Explanation:

The expression for the  trigonometric function is :

L(t) = A (cos (B(t - C)))+ D   ----- equation (1)

where ;

A = \frac{max-min}{2}

A = \frac{0.25-0}{2}

A = 0.125

D = \frac{0+.025}{2}

D = 0.125

Period of the lunar cycle = 29.53

Then;

\frac{2 \pi}{B}  = 29.53

29.53 \ \ B = 2 \pi

B = \frac{2 \pi}{29.53}

B = \frac{\pi}{29.53}

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\  ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}

( cos ( \frac{\pi}{14.765}((-7)-C))) = 1

( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)

}((-7)-C))=0

C= -7

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

7 0
3 years ago
I am a bit confused about this question.
gavmur [86]

How do you know when something is moving ?  You ALWAYS have to compare it to something else.  If the object in question changes its distance or direction from your house, or from your big toe, or from a stake in the ground in your front yard, then you say it's moving.  The thing is:  There's ALWAYS something else to compare it to.

I assume you're sitting on the couch now, staring at the TV, or at your computer, or at your phone.  Compared to the couch, or to the tree in your front yard, or to somebody sitting on top of Mt. Everest, or to downtown Jerusalem, you're NOT moving.  Your distance and direction from the reference point isn't changing.

BUT ... what if you compare yourself to somebody sitting at the North pole of the Sun ?  He has to keep turning his eyes to watch you (because the Earth including you is in orbit around the sun).  So your direction from him keeps changing, and 'relative' to him (compared to him), you're definitely moving.

Now let's go a little farther:  

You're sitting in a comfy seat, reading a book that's in your lap.  Maybe you're even getting sleepy.  You're sitting still in the seat, and the book in your lap isn't moving.

SURPRISE !  Your comfy seat is in Row-27 of a passenger jet, and you're flying to Seattle to visit your Grandma.  right now, you're just passing over Casper, Wyoming, and there's somebody down on the ground playing with a telescope.  He looks at your airplane, and HE says that you, the seat you're sitting in, and your book are ALL moving at almost 500 miles an hour.

The difference is:  YOU're comparing your book to the seat in front of you, and YOU say the book is not moving.  The guy with the telescope is comparing the book to the ground he's standing on, and HE says your book is moving west at 500 miles an hour.

You're BOTH correct.  The description of ANY motion always depends on what you're comparing to.  If you're about to ask "What's the REAL motion of the book ?", then I'm sorry.  There's NO SUCH THING as 'REALLY'.  It always depends on what you're comparing to.  Nine people can be watching the same object, and they can have nine different descriptions of its motion, and they're ALL correct.  They're just comparing the object to different things in their own neighborhood, and the nine things are all moving in different ways.

The bottom line:  MOTION IS ALWAYS RELATIVE (to something else).

8 0
3 years ago
A 500 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert
liberstina [14]

Answer:

x = 7.62 m

Explanation:

First we need to calculate the weight of the rocket:

W  = mg

we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:  

W  = 0.5 * 9.8 = 4.9 N

We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:

F - W = m*a

a = F - W/m

Solving for a:

a = (8 - 4.9) / 0.5

a = 6.2 m/s²

As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:            

y = vo*t + 1/2 at²

y = 1/2at²

Solving for t:

t = √2y/a

t = √2 * 20 / 6.2

t = √6.45 = 2.54 s

Now that we have the time, we can calculate the horizontal distance:

x = V*t

Solving for x:

x = 3 * 2.54 = 7.62 m            

4 0
4 years ago
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