"Constant velocity" is another way of saying "zero acceleration".
Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to
for θ
I(x) =
y²p dA
I(x) =
(a sinθ)²(k × a²) adθda
I(x) = k
da ×
(sin²θ)dθ
I(x) = k
da ×
(1-cos2θ)/2 dθ
I(x) = k
×
I(x) = k ×
× (
I(x) = k ×
×
I(x) = 1444×k ×
.....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k ×
......................2
Explanation:
As the given data is as follows.
ohm
,
ohm,
= 1200
(as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance = 
=
ohm
= 2600 ohm
or, = 2.6
ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6
ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance = 
= 
=
ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is
ohm.
Answer:
The option is B is not true for Hubble telescope.