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telo118 [61]
3 years ago
12

2H2 + O2 = 2H2O is a neutralization or non-neutralization reaction? And explain why..

Chemistry
1 answer:
Gemiola [76]3 years ago
6 0
This is a neutralization reaction since, the hydrogen ion, H+, from the HCl is neutralized by the hydroxide ion, OH-, from the KOH to form the water molecule, H2O and salt, KCl only.
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Watch the animation and observe the titration process of a standard 0.100 M sodium hydroxide solution with 50.0 \rm ml of a 0.10
yuradex [85]

Answer:

Answers are in the explanation

Explanation:

a. The statments are:

The titration process is based on a chemical reaction.  <em>TRUE. </em>A titration is the chemical reaction between an acid and a base.

The pH of the solution at the equivalence point is 7.  <em>TRUE. </em>In a titration of strong acid with strong base the equivalence point is 7

At the endpoint, the pH of solution is 10 and the color of solution is pink.  <em>FALSE</em>. The endpoint in a strong acid - strong base titrationmust be near to equivalence point at pH = 7.

At the beginning of the titration process, the pH of the solution increases rapidly.  <em>FALSE. </em>At beginning of a titration, the pH of the solution increases slowly.

The chemical reaction involved in an acid-base titration is a neutralization reaction.  <em>TRUE. </em>In the reaction, you are neutralizing an acid (HCl) with a base (NaOH)

Before any base is added to the solution, the pH of the solution is high. <em>FALSE. </em>The addition of a base increases pH that is, in the beginning, low.

In a titration process, the endpoint is reached before the equivalence point.  <em>FALSE. </em>In a titration process, the endpoint is reached in the equivalence point

The pH of the solution changes very slowly at the equivalence point. <em>FALSE. </em>At the equivalence point, the pH changes rapidly.

b. For the reaction

NaOH + HCl → H₂O + NaCl

As the reaction is 1:1 and molarity of both solutions are the same, additions < 100mL of NaOH will stay before the equivalence point, equivalence point will be in 100mL and additions > 100mL of NaOH will stay after the equivalence point.

The conditions are:

10.0mL of 1.00 M NaOH before the equivalence point

150 mL of 1.00 M NaOH after the equivalence point

5.00 mL of 1.00 M NaOH before the equivalence point

50.0 mL of 1.00 M NaOH  before the equivalence point

200 mL of 1.00 M NaOH after the equivalence point

I hope it helps!

7 0
3 years ago
Read 2 more answers
What weight of sodium formate must be added to 4.00L of 1.00 M formic acid to produce a buffer solution that has a pH of 3.50?
tester [92]

Answer:

156,4 g of sodium formate

Explanation:

The pka of the formic acid is 3,74. Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A⁻] / [HA] <em>(1)</em>

Where A⁻ is the conjugate base (Formate) and HA is the formic acid.

4.00L of 1.00M formic acid contain:

4.00L × (1.00mol /L) = 4.00 moles

Replacing these moles, the desired pH and the pka value in (1):

3,50 = 3,74  log₁₀ [A⁻] / 4,00 moles

-0,24 =  log₁₀ [A⁻] / 4,00 moles

0,575 = [A⁻] / 4,00 moles

<em>2,30 moles = [A⁻] </em>

That means you need 2,30 moles of formate (Sodium formate), to produce the desired buffer. As the molar mass of sodium formate is 68,01g/mol, the weight of sodium formate that must be added is:

2,30mol×(68,01g/mol) =<em> 156,4 g of sodium formate</em>.

I hope it helps!

7 0
3 years ago
How many grams of Tin (SN) would be required to use 6.9 moles of chlorine (cl2)
Ipatiy [6.2K]
Sn  +  Cl₂   →  SnCl₂

mole ratio of Cl₂  :  Sn  is   1 :  1
∴ if moles of Cl₂  =  6.9 mol
 then moles of Sn = 6.9 mol

Mass =  moles × molar mass

          =  6.9 mol  × 119 g/mol
 
          =  821.1 g



8 0
3 years ago
In the biosphere, prey represent a food source for predators. An increase in the population of prey means more food for predator
mote1985 [20]
<h2>Answer:</h2>

An increase in the population of prey means more food for predators, which will<u> increase</u> the predators' population. As a result, many more prey will be hunted, causing the prey population to<u> decrease.</u> In response, the predator population will <u>decrease</u>, resulting in an increase in the prey population.

<h3>Explanation:</h3>

The feedback loop is control of the system containing the prey and predator.

In this loop, the population of predator is directly proportional to prey but the population of prey is inversely proportional to a predators population.

As the population of prey increases, the population size of predator becomes large due to the availability of food. This inversely decreases the population of prey, as the predator do more hunt.

So the decrease in prey population results in a decrease in the predator population.

5 0
3 years ago
Read 2 more answers
Which endocrine gland is nick named as "THIRD EYE"
PSYCHO15rus [73]

Answer:

Its answer is

c)pineal gland

4 0
3 years ago
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