A book weighing 2 Newtons is at rest on a table. The net force on the book is zero.

Pleaseee HElpp!!!!!!!

lutik1710 [3]

Coulomb's Law

Given:

F = 3.0 x 10^-3 Newton

d = 6.0 x 10^2 meters

Q1 = 3.3x 10^-8 Coulombs

k = 9.0 x 10^9 Newton*m^2/Coulombs^2

Required:

Q2 =?

Formula:

F = k • Q1 • Q2 / d²

Solution:

So, to solve for Q2

Q2 = F • d²/ k • Q1

Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9 Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)

Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)

Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)

Then, take the reciprocal of the denominator and start multiplying

Q2 = 1080 • 1 Coulombs/297

Q2 = 1080 Coulombs / 297

Q2 = 3.63636363636 Coulombs

Q2 = 3.64 Coulumbs

6 0

3 years ago

Read 2 more answers

A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p

saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, $x$ , of an SHM is given by

$x = A\cos(\omega t)$

A is the amplitude and $\omega$ is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or $\frac{\pi}{4}$ radian.

From trigonometry, $\sin A =\cos B$ if A and B are complementary.

At $t = 0$ , $x = 3.5$

$3.5 = A\cos(\omega \times0)$

$A =3.5$

So

$x = 3.5\cos(\omega t)$

At $t = 0.12$ , $x = 1.5$

$1.5 = 3.5\cos(0.12\omega)$

$\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286$

$0.12\omega =\cos^{-1}0.4286$

$0.12\omega = 1.13$

$\omega = 9.4$

The period, $T$ , is related to $\omega$ by

$T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67$

5 0

3 years ago

Yay maybe okay so yeah

e-lub [12.9K]

Answer:

what?

Explanation:

7 0

3 years ago

Read 2 more answers

A pendulum consists of a weight tied by a string that is attached to the ceiling. The diagram models the motion of the pendulum

Mashutka [201]

Pendulum under goes energy conversions from potential to kinetic and back to potential.

A pendulum consists of a long string to which a bulb is attached. The string is fastened to a point from which it can oscillate freely when displaced through a small angle.

The pendulum is an example of a system in which energy conversion takes place. The energy is converted from potential to kinetic and back to potential. Since the image was not shown in the question, we can not locate the specific points where the energy conversions occur.

Learn more: brainly.com/question/14759840

6 0

3 years ago

A car traveling west in a straight line on a highway decreases its speed from 30.0 meters per second to 23.0 meters per second i

pychu [463]

Acceleration, a = (v - u) / t

Initial Velocity, u = 30 m/s
Final Velocity, v = 23 m/s
time t = 2.00 seconds

a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2

So the acceleration is negative, which means it is a deceleration of 3.5 m/s2.

8 0

3 years ago