Answer:
Explanation:
Thermal Efficiency=0.98*0.84=0.8232
Total energy produced=2784.3*0.98+2041.6*0.84+340.5+346.6=5150.658 kJ/kg
Toal coal consumed=2.1*10^9*3600/5130.658=1473495.213 tonnes
Total cost=4.42*10^7 $
Mass of CO2 produced=Total Coal consumed*(Mass of CO2/Mass Of C)=54028158.11 tonnes
Mass of CO2/million kWH=25727.694
OR
Work done by turbine(Wt)
=(h1-h2) = 2784.3 - 2041.6 = 742.7 KJ/Kg
Work done on Pump(Wp) = (h4-h3) = 6.1 KJ/kg
Work Done by Boiler(Wb) = (1/efficiency)*(h1-h4) =(1/0.84) *(2784.3-346.6) = 2902.02 KJ/Kg
Thermal Efficiency = (Wt-Wp)/Wb = 25.38 Percent
Total Work by Turbine = (1/0.98)*2.1 Billion KW-hr/year
Total Coal Energy = (1/0.2538)*(1/0.98)*2.1 Billion KW-hr/year = 8.443 Billion KW-hr/year
Toatal coal required for an year
m*742.7 = (1/0.98)*2.1 Billion KW-hr/year = (1/0.98)*2.1*10^9*60 KJ/year
m = 1731.14 Tonnes
annual coal cost =1731.14*30 = 51934.2 dollars
2 metric tons of CO2 per one Kilowatt-hour (from graph)
Total CO2 emission = 2.1*10^9*2 = 4.2 Billion Metric tonnes
Total CO2 emitted per million KW-hr Produced = 2 million Metric tons