K will always have an oxidation state of +1. Now O is -2 except in peroxides, this is not a peroxide, so total charge will be -6, if you subtract the +1 of K from it, it leaves -5 charge to be neutralized by Cl in KClO3, so Cl will be +5. In the product side, K will still have the same oxdiation which is +1 and Cl would have -1. O2 will have zero. <span>Now, Cl is gaining the electrons to go from +5 to -1, so it is getting reduced while O2 is losing electrons to go from -2 to zero so it is getting oxidized.</span>
Answer:
noun. the composite or generally prevailing weather conditions of a region, as temperature, air pressure, humidity, precipitation, sunshine, cloudiness, and winds, throughout the year, averaged over a series of years. a region or area characterized by a given climate: to move to a warm climate.
Explanation:
Option B: 4.3
There are following rules for rounding off numbers:
1. If the rounding digit has digit less than 5 (1,2,3 and 4) to its right, all the digits on right side of the rounding digit will drop out.
2. If the rounding digit has digit equal and greater than 5 (5,6,7,8 and 9) to its right, one is added to the rounding digit.
Jeff has to weigh 4.312 g sample of NaCl. To round off the underline number 4.<u>3</u>12, check for the digit right to it. It has 1, which is less than 5 thus according to the Rule 1, all the digits on right side of the rounding digit will drop out and the number gets rounded off to 4.3.
Therefore, 4.3 is most accurate measurement by Jeff.
Answer:
The enthalpy change for the reaction is ΔH = - 54.3 kJ/mol
Explanation:
The reaction between HCl and NaOH is a neutralization reaction:
Heat released during neutralization = Heat gained by water
i.e. 
where:
m = total mass of solution
ΔT = change in temperature = 22.8 - 21.5 = 1.3 C
c = specific heat = 4.18 J/g C
As per equation (1): qrxn = -434.7 J
The reaction enthalpy ΔH is the heat released per mole of acid (or base)
Answer:
58.44 g/mol
Explanation:
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