What substances is the most soluble in water?

Copper reacts with silver nitrate through single replacement.

-Dominant- [34]

Answer:

Part a) 0.0104 moles copper(II) nitrate.

Part b)

i) 0.0418 mole Cu

ii) 0.0209 mol Ag NO₃

Explanation:

1) Balanced chemical reaction (single replacement):

In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)

Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag

2) Mole ratio:

1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag

3) Moles of Ag

n = mass in grams / atomic mass
atomic mass of Ag: 107.868 g/mol
n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag

4) Moles of copper(II) nitrate:

Set the proportion using the mole ratio:

2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x

Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ = 0.0104 moles Cu(NO₃)₂

That is the answer of part a: 0.0104 moles copper(II) nitrate.

5) Moles of each reactant

i) Cu:

Set a proportion using the theoretical mole ratio

1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag

Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu

ii) Ag NO₃

Set a proportion using the teoretical mole ratio

2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag

Solve for x: x = 0.0209 mol Ag NO₃

6 0

4 years ago

I'm looking at the barometer in my lab as I type this question. It says the pressure is 968 torr. What is this pressure expresse

Ksenya-84 [330]

Answer:

1.27 atm.

Explanation:

The following data were obtained from the question:

Pressure (P) in torr = 968 torr

Pressure (P) in atm =...?

Thus, we can convert from torr to atm by doing the following:

Recall:

760 torr = 1 atm

Therefore,

968 torr = 968/760 = 1.27 atm

Therefore, 968 torr is equivalent to 1.27 atm.

7 0

3 years ago

What are the representative elements? Where are they located

WINSTONCH [101]

The representative elements are elements where the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3–11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.

4 0

3 years ago

Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if 2 moles of pentane (C5H12) were supplied, and an unlimited amount

Kamila [148]

12 moles of water H₂O are produced from the combustion of pentane.

Explanation:

We have the following combustion of pentane (C₅H₁₂):

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

Knowing the chemical reaction we devise the following reasoning:

if 1 moles of pentane C₅H₁₂ produces 6 moles of water H₂O

then 2 moles of pentane C₅H₁₂ produces X moles of water H₂O

X = (2 × 6) / 1 = 12 moles of water H₂O