Answer: 1.653 × 10⁴ N/C
Explanation: Given Q= 3.6× 10^-6
we assume there is a charge q placed at a distance r = 1.4m exerting an electric field strength towards Q.
Hence
F = kQq/r²
K= 9× 10^9
Now recall that E = F/q (electric field due to that charge)
E =( kQq/r²)/q
E = kQ/r² substituting the values gave the answer above.
Answer: use use a ruler and measure, then add to the arrows
Explanation:
So the problem are asking to find the value of G base on the formula of the said equation of the magnitude of gravitational attraction on either body. Base on that, the possible answer or the derived formula of the said function is G = Fr^2/m1m2. I hope you are satisfied with my answer and feel free to ask for more
Answer:
Charge, q = 900 C
Explanation:
It is given that,
Current flowing through the circuit, I = 6 A
Time for the flow of current, t = 2.5 minutes = 150 seconds
We have to find the charge delivered to this circuit. The total charge per unit time is called the current flowing through the circuit. It q is the charge flowing, then :
q = I × t
q = 6 A × 150 s
q = 900 coulomb
So, 900 coulomb of charge is delivered to this circuit.
Answer:
efferent pathway
Explanation:
efferent pathway - it is the pathway used by signal to get away from the nervous system. After getting signal from the brain, efferent signal direct body to do according to the received signals.
while on the other side, afferent signals related to the signal that sends by the body to the brain. which is opposite to the efferent signals