If an object is thrown in an upward direction from the top of a building 1.60 x 102 ft. high at an initial velocity of 21.82 mi/h, what is its final velocity when it hits the ground? (Disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)
this question is troubling me i guessed 96 ft/s
can someone help me out and explain it thanks so much!!!!!!
Answer:
80 amperes
Explanation:
Current in the circuit = ?
Voltage in the circuit = 160 Volts
Resistance = 2 Ω
Voltage = Current x Resistance
V = IR
160V = I x 2 Ω
I = 160V / 2 Ω
I = 80 Amperes
Therefore the current in the circuit is 80 amperes :)
The bearing could be the below:
oppositely charged, same initial direction
same charge, opposite initial direction
You can decide by utilizing your correct hand and put your fingers toward the attractive field (North to South). Thumb toward present or charged molecule. The course of your palm will demonstrate the heading of compelling set on a decidedly charged molecule and the bearing of the back of your hand will demonstrate the bearing of a contrarily charged molecule.
Most often those smaller structures are triangular in shape because triangular shapes are very strong and stable
Hello!
Recall the equation for gravitational force:
Fg = Force of gravity (N)
G = Gravitational constant
m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)
There is a DIRECT relationship between mass and gravitational force.
We are given:
If we were to double one mass and triple another, according to the equation:
Thus:
