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Lisa [10]
3 years ago
9

A sports car accelerates from rest at 4 metre per second squared for 10 seconds , its final velocity would be?

Physics
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer:

40m/s

Explanation:

s= NOT NEEDED

u= 0

v= ?

a=4m/s^2

t=10

find the equation

v=u+at

substitute in values:

v=0+4x10

v=40m/s

just olya [345]3 years ago
6 0

Answer:

I'm not sure

Explanation:

Because I dont

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3 years ago
A whistle of frequency 564 Hz moves in a circle of radius 71.2 cm at an angular speed of 17.1 rad/s. What are (a) the lowest and
trapecia [35]

Answer:

a) f'=544.66 \textup{Hz}

b) f'=584.75 \textup{Hz}

Explanation:

Given:

Frequency of the whistle, f = 564 Hz

Radius of the circle, r = 71.2 cm = 0.712 m

Angular speed, ω = 17.1 rad/s

speed of source, v_s = rω = 0.712 × 17.1 = 12.1752 m/s

speed of sound, v = 343 m/s

Now, applying the Doppler's effect formula, we have

f'=f\frac{v\pm v_d}{v\pm v_s}

where,

v_d = relative speed of the detector with respect to medium = 0

a) for lowest frequency, we have the formula as:

f'=f\frac{v}{v+v_s}

on substituting the values, we get

f'=564\times\frac{343}{343+12.1752}

or

f'=544.66 \textup{Hz}

b) for maximum frequency, we have the formula as:

f'=f\frac{v}{v-v_s}

on substituting the values, we get

f'=564\times\frac{343}{343-12.1752}

or

f'=584.75 \textup{Hz}

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