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Lisa [10]
3 years ago
9

A sports car accelerates from rest at 4 metre per second squared for 10 seconds , its final velocity would be?

Physics
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer:

40m/s

Explanation:

s= NOT NEEDED

u= 0

v= ?

a=4m/s^2

t=10

find the equation

v=u+at

substitute in values:

v=0+4x10

v=40m/s

just olya [345]3 years ago
6 0

Answer:

I'm not sure

Explanation:

Because I dont

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What is the difference between Is it resource that is limited and one that is not limited? Give an example of each
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A ball is dropped from a height h and falls the last half of its distance in 4 seconds. How long does the ball fall? From what h
dlinn [17]

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3 years ago
A bobsledder pushes her sled across horizontal snow to get it going, then jumps in. After she jumps in, the sled gradually slows
anastassius [24]

Answer:

In the vertical direction the acting forces are the normal force and the weight of the bobsleder plus the sled. In the horizontal direction the acting force is the friciton force.

Explanation:

Hi there!

Please, see the attached figure for a graphic representation of the forces acting on the sled after the bobsleder jumped in.

In the vertical direction, the acting forces are the normal force (N) and the weight of the sled plus the bobsledder (W).

Since the sled is not being accelerated in the vertical direction, the sum of forces in that direction is zero:

∑Fy = W + N = 0 ⇒ W = N

The weight is calculated as follows:

W = (mb + ms) · g

Where:

mb = mass of the bobsleder.

ms = mass of the sled.

g = acceleration due to gravity.

In the horizontal direction the only acting force is the friction force (Fr). The friction force is calculated a follows:

Fr = N · μ

Where:

N = normal force.

μ = kinetic friction coefficient.

Since N = W = (mb + ms) · g

Fr = (mb + ms) · g · μ

If we want to find the acceleration of the sled after the bobsleder jumps in, we can apply Newton's second law:

∑F = m · a

Where "a" is the acceleration and "m" is the mass of the object (in this case, the mass of bobsleder plus the mass of the sled).

∑F = Fr =  (mb + ms) · g · μ =  (mb + ms) · a

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3 0
3 years ago
what is the pressure exerted, what is the pressure exerted by 50kg girl as she places her weight on one shoe if the heels area i
lana [24]

Answer:

The pressure exerted by the girl is 245,000 N/m²

Explanation:

Given;

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Therefore, the pressure exerted by the girl is 245,000 N/m²

6 0
3 years ago
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