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vampirchik [111]
3 years ago
11

You are cycling around a circular track at a constant speed. Does the magnitude of your acceleration change? The direction?

Physics
1 answer:
konstantin123 [22]3 years ago
3 0

Answer: A) The magnitude and direction of the acceleration change.

Explanation:

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Select all that apply.
lutik1710 [3]

Answer: Virtual, upright and diminished.

Explanation:

A transparent material that focuses or diverges light is known as a lens. There are mainly two types of lens: concave lens and convex lens. Other lens can be made using combination of these two and plane one.

A concave lens is a diverging lens. It means the light from any real object after passing through this lens appears to diverge from the focus. A image formed by a diverging lens is virtual, upright and diminished.


4 0
3 years ago
Read 2 more answers
Which of the following frequencies falls in the range of RF waves used by commercial radio broadcasting stations?
dybincka [34]
<span>  A. 6,000,000 Hz =3 they were correct</span>
8 0
3 years ago
Read 2 more answers
high school physics, no need detail explain, just give the answer, but you have to make sure thank you
andrey2020 [161]

Answer:

approximately 30 degrees

Explanation:

If it takes the cannonball 2 seconds to reach the maximum height, we can use the analysis of the vertical component of the velocity and the fact that the acceleration of gravity is the one acting opposite to this initial vertical component (v_y) of the velocity. We know as well that at the top of the trajectory, the vertical component of the velocity is zero, and then the movement starts going down in it trajectory. So, the final velocity for the first part of the ascending movement is zero, giving us the following equation for the velocity under an accelerated movement (with acceleration of gravity "g" acting):

v_f=v_i-a\,t\\v_f=v_y-g\,t\\0=v_y-9.8\,*\,2\\v_y=9.8\,*\,2=19.6 \frac{m}{s}

By knowing the vertical component of the initial velocity (19.6 m/s), and the actual magnitude of the total initial velocity (40 m/s), we can calculate what angle was the initial velocity vector forming above the horizontal. We use for such the fact that the sine of the angle relates the opposite side of a right angle triangle with the hypotenuse, and solve for the angle using the arcsin function:

sin(\theta)=\frac{opp}{hyp} \\sin(\theta)=\frac{19.6}{40}\\\theta=arcsin(\frac{19.6}{40})\\\theta=29.34^o

which tells us that the closer answer shown is 30^o

7 0
4 years ago
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position
irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

  • <em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz

The angular frequency of the oscillation is calculated as follows;

\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s

The force constant of the spring is calculated as follows;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m

Learn more about general wave equation here: brainly.com/question/25699025

4 0
3 years ago
When the compressor of an air conditioner starts up, it draws a current of 50 A. If the start-up time is 0.60 s, then the amount
7nadin3 [17]

Answer:

30 C

Explanation:

Given:

Current flowing in the circuit (I) = 50 A

Start-up time (t) = 0.60 s

Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:

q=It

Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.

Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,

q=50\ A\times 0.60\ s\\\\q=30\ C

Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.

6 0
3 years ago
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