Answer:
A3tx-A2b=cdx-2c
Step-by-step explanation:
Distribution
if the tins are shown like this:
TIN A: 2:3
TIN B: 4:5
TIN A: can also be shown as 4:6
there for theirs is more blue in the first tin then second tin
<span>2x/4x+2 x 14 x+7/6 is unclear. Do you mean 2/4x, or do you mean 2x
-------- ??
4x+2
Use parentheses to make things clearer.
I will assume that you meant to write
2x
--------- * 14x + 7/6
4x + 2
but am very much unsure if this is correct or not.
Perhaps you meant
</span>2x/(4x+2) times 14(x+7/6)
<span>
This comes out as follows:
2x * 14 (x + 7/6) 28x(x + 7/6) 14x(x + 7/6)
------------------------ = ------------------- = --------------------
4x+2 2(2x + 1) 2x + 1 after reduction.
Performing the multiplication, we get 14x^2 + 98/6
--------------------
2x+1
</span>
It appears that you're using "x" both as a variable name and as the "multiply" operator. If so, please don't! Use " * " to indicate multiplication.
<span>
</span>Please take and share a screen shot of this problem.
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have
When t = 0, A(0) = 0 (since the forest floor is initially clear)
So, D = R - A =
when t = 0(at initial time), the initial value of D =