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hichkok12 [17]
3 years ago
12

What are the advantages of strength exercises?

Physics
1 answer:
Sever21 [200]3 years ago
3 0

Answer: Well some advantages of strength is the fact that: you have a stronger heart, Immune system, more energy, life span, stamina, positive thoughts, and also believe it or not. An easier connection with the deeper part of earth

Explanation:

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Gravity is a force that helps to hold the universe together.true or false
Valentin [98]
Yes, this is a true statement.



gravity is so important.
7 0
3 years ago
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An athlete kicks a soccer ball that starts at rest so that it leaves their foot with a speed of 10m/s from the top o f a rectang
kirza4 [7]

Answer:

a=500m/s^2

Explanation:

We need only to apply the definition of acceleration, which is:

a=\frac{v_f-v_i}{t_f-t_i}

In our case the final velocity is v_f=10m/s, the initial velocity is v_i=0m/s since it departs from rest, the final time is t_f=0.02s and the initial time we are considering is t_i=0s

So for our values we have:

a=\frac{10m/s-0m/s}{0.02s-0s}=500m/s^2

3 0
3 years ago
The focal length for a spherical convex mirror is –20 cm. What is its radius of curvature?
Svetradugi [14.3K]

Answer:

40 cm

Explanation:

The focus of a spherical convex mirror is the point at which the rays of an object converge in the infinite, it is also the point at which an object must be placed so that its image is formed in the infinite. The distance from the focus to the origin is called the focal length and is called f. It is related to the radius of the mirror, R, according to:

f=-\frac{R}{2}

rewriting for R:

R=-2f=-2*-20cm=40 cm.

4 0
3 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
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What are the size and direction of the force that is the sum of a force of 3 n acting south and a force of 6 n acting north?
V125BC [204]
The resultant force is 3 N north.
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3 years ago
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