By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span>
=>v¹ = 2.25 m/s (East) </span>
Answer:
Radius of the loop is 0.18 m or 18 cm
Explanation:
Given :
Current flowing through the wire, I = 45 A
Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T
Number of turns in circular wire, N = 1
Consider R be the radius of the circular wire.
The magnetic field at the center of the current carrying circular wire is determine by the relation:
Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.
Substitute the suitable values in the above equation.
![1.50\times10^{-4} =\frac{4\pi \times10^{-7}\times45 }{2R}](https://tex.z-dn.net/?f=1.50%5Ctimes10%5E%7B-4%7D%20%3D%5Cfrac%7B4%5Cpi%20%5Ctimes10%5E%7B-7%7D%5Ctimes45%20%7D%7B2R%7D)
R = 0.18 m
Answer:
a. one-half as great
Explanation:
The power developed by the first lifter is one-half as great as that of the second person.
Power is defined as the rate at which work is done;
Power =
Since the two lifters do the same work at different time, let us estimate their power;
P₁ =
P₂ =
We see that for P₁, power is half of the work done whereas in P₂ power is the same as the work done.
Therefore,
The power of the first weight lifter is one-half the second lifter.
Answer:
In a controlled experiment, an independent variable (the cause) is systematically manipulated and the dependent variable (the effect) is measured; any extraneous variables are controlled. The researcher can operationalize (i.e. define) the variables being studied so they can be objectivity measured.
Answer:
![d =4.77\times 10^{-5}\ m](https://tex.z-dn.net/?f=d%20%3D4.77%5Ctimes%2010%5E%7B-5%7D%5C%20m)
Explanation:
given
wavelength of light λ = 479 nm
= 479 x 10⁻⁹ m
the angle
θ = 1.15 / 2 = 0.575°
using
condition for diffraction minimum ,
d sinθ = m λ
for first minimum m = 1
d sinθ = λ
therefore ,
slit width
![d =\dfrac{479\times 10^{-9}}{sin 0.575^0}](https://tex.z-dn.net/?f=d%20%3D%5Cdfrac%7B479%5Ctimes%2010%5E%7B-9%7D%7D%7Bsin%200.575%5E0%7D)
hence, the width of the slit is equal to ![d =4.77\times 10^{-5}\ m](https://tex.z-dn.net/?f=d%20%3D4.77%5Ctimes%2010%5E%7B-5%7D%5C%20m)