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Leviafan [203]
3 years ago
10

Ô tô có khối lượng 2500kg

Physics
1 answer:
Galina-37 [17]3 years ago
6 0

Answer:

  1. <em><u>jsksjsjsj</u></em><em><u>sjsjnznxosbdisnsjjwkjejwjkksoddjndomswsl</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><u>qowoapoooen</u><u> </u><em>kwmwkkwmem</em><em><u> </u></em><em><u>make</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>laugh</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>get</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>you</u></em><em><u>?</u></em><em><u>?</u></em><em><u> </u></em><em><u>edit</u></em><em><u>!</u></em><em><u> </u></em><em><u>thanks</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>just</u></em><em><u> </u></em><em><u>going</u></em><em><u> </u></em><em><u>through</u></em><em><u>.</u></em><em><u> </u></em><em><u>com</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>few</u></em><em><u> </u></em><em><u>weeks</u></em><em><u> </u></em><em><u>before</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>bad</u></em><em><u> </u></em><em><u>at</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>beginning</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>amazing</u></em><em><u> </u></em><em><u>how</u></em><em><u> </u></em><em><u>many</u></em><em><u> </u></em><em><u>things</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>rest</u></em><em><u>.</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>way</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>they</u></em><em><u> </u></em><em><u>want</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>new</u></em><em><u> </u></em><em><u>one</u></em><em><u>?</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>best</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>this</u></em>
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Are you an antisocial person. Me honestly am
gregori [183]

Explanation:

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If you tell me the meaning of it, I'll tell you my answer too(ㆁωㆁ)

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3 years ago
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Determine the specific heat of a certain metal if a 450 gram sample of it loses 34 500 Joules of heat as its temperature starts
slamgirl [31]

Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

Final temperature, T2 = 53°C

Quantity of heat = 34500 Joules

To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 53 - 150

dt = -97°C

Converting the temperature in Celsius to Kelvin, we have;

dt = 273 + (-97) = 176 Kelvin

Making c the subject of formula, we have;

c = \frac {Q}{mdt}

Substituting into the equation, we have;

c = \frac {34500}{450*176}

c = \frac {34500}{79200}

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6 0
3 years ago
(a) Write an equation describing a sinusoidal transverse wave traveling on a cord in the positive of a y axis with an angular wa
Vedmedyk [2.9K]

Missing data: the wave number

k=60 cm^{-1}

(a)  z = 0.003 sin (6000y-31.4 t)

For a transverse wave travelling in the positive y-direction and with vibration along the z-direction, the equation of the wave is

z = A sin (ky-\omega t)

where

A is the amplitude of the wave

k is the wave number

\omega is the angular frequency

t is the time

In this situation:

A = 3.0 mm = 0.003 m is the amplitude

k = 60 cm^{-1} = 6000 m^{-1} is the wave number

T = 0.20 s is the period, so the angular frequency is

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.20}=31.4 rad/s

So, the wave equation (in meters) is

z = 0.003 sin (6000y-31.4 t)

(b) 0.094 m/s

For a transverse wave, the transverse speed is equal to the derivative of the displacement of the wave, so in this case:

v_t = z' = -A \omega cos (ky-\omega t)

So the maximum transverse wave occurs when the cosine term is equal to 1, therefore the maximum transverse speed must be

v_{t}_{max} =\omega A

where

\omega = 31.4 rad/s\\A = 0.003 m

Substituting,

v_{t}_{max}=(31.4)(0.003)=0.094 m/s

(c) 5.24 mm/s

The wave speed is given by

v=f \lambda

where

f is the frequency of the wave

\lambda is the wavelength

The frequency can be found from the angular frequency:

f=\frac{\omega}{2\pi}=\frac{31.4}{2\pi}=5 Hz

While the wavelength can be found from the wave number:

\lambda = \frac{2\pi}{k}=\frac{2\pi}{6000}=1.05\cdot 10^{-3} m

Therefore, the wave speed is

v=(5)(1.05\cdot 10^{-3} )=5.24 \cdot 10^{-3} m/s = 5.24 mm/s

7 0
3 years ago
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A how our planets and moons formed
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bagirrra123 [75]
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\lambda= \frac{c}{f}
Using the data of the problem, we find
\lambda= \frac{3\cdot 10^8 m/s }{7.20 \cdot 10^{21} Hz}=4.17 \cdot 10^{-14} m
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3 years ago
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