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noname [10]
2 years ago
15

If an atom of Phosphorous has 17 neutrons, what is its mass number?

Chemistry
1 answer:
Alina [70]2 years ago
4 0
Mass number = number of protons + number of neutrons

The number of protons in the nucleus of an atom of phosphorus is equal to the atomic number of phosphorus, which is 15. If an atom of phosphorus has 17 neutrons, then the mass number would be 15 protons + 17 neutrons = 32. Thus, the correct answer choice here is B.
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How many moles are in 20 grams of Ar?​
pashok25 [27]

Answer:

moles Ar in 20g = 0.500 mole Ar

Explanation:

moles = grams given / formula weight = 20g / 39.948g·mol⁻¹ = 0.500 mole Ar

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2 years ago
Which of these bonds is the weakest?​
Olenka [21]

Answer:

The first one has the weakest bond

Explanation:

The number of atoms together shows how strong the bonds in the second bond it is 4 bonds, the third is 8 bonds, the 4th one is 4 bonds thus why the first bond is the weakest.

6 0
2 years ago
Plz help me I am timed
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C. interior plains

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sana makatulong

8 0
2 years ago
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3 0
3 years ago
3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh
TiliK225 [7]

Answer:

n_{C_6H_{10}}=0.03molC_6H_{10}

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}

Even thought, the volume could be also computed by using its density:

V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}

Best regards.

4 0
2 years ago
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