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Alex787 [66]
3 years ago
9

5. Water is known to have a composition which is 88.8% oxygen by mass. If you had a

Chemistry
1 answer:
Fantom [35]3 years ago
4 0
Oxygen : 367*0.888=325.896
Hydrogen : 367 - 367*0.888 = 41.104g
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What is the key structural feature of all Brønsted-Lowry bases? How does this feature function in an acid-base reaction?
Fiesta28 [93]

Key feature of a Bronsted Lowry base : The notable feature of all bronsted lowry bases is that they contain atleast one electron lone pair, which is available for interaction with a proton, and allows the base to act as a proton acceptor.

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3 0
1 year ago
PLEASE HELP THOSE WHO ARE CHEMISTS!! How many molecules are there in 79g of Fe2O3? How many atoms is this?
Shtirlitz [24]
<span><span>1.       </span><span>Fe2O3 or Iron (III) oxide is an organic compound. It contains 3 main oxides of Iron, the iron (II) oxide (FeO) and the iron (II, III) oxide (Fe3O4).

Now, let’s find the number of Molecules are there in 79g of Fe203:
The number of Atoms are there:

Molar Mass of Fe2O3 = 160g / mol.
=> 160g  of Fe2O<span>3  </span>= 6.02 x 1023 Molecules
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8 0
3 years ago
How many moles of ions form when 51.0 g of calcium iodide is dissolved in water? how many ions form?
vredina [299]

Answer : The number of moles of ions form are, 3.14\times 10^{23} and there are 3 ions formed.

Explanation :

First we have to calculate the moles of calcium iodide.

\text{Moles of }CaI_2=\frac{\text{ given mass of }CaI_2}{\text{ molar mass of }CaI_2}

Molar mass of calcium iodide = 293.9 g/mol

Mass of calcium iodide = 51.0 g

\text{Moles of }CaI_2=\frac{51.0g}{293.9g/mole}=0.174moles

Now we have to calculate the number of moles of ions.

As we know that when calcium iodide dissolved in water then it dissocites to give calcium ion and iodide ion.

The balanced chemical reaction will be:

CaI_2(aq)\rightarrow Ca^{2+}(aq)+2I^{-}(aq)

From this we conclude that there are 3 ions formed.

As, 1 mole of calcium iodide dissociate to give 3\times (6.022\times 10^{23}) number of ions

So, 0.174 mole of calcium iodide dissociate to give 0.174\times 3\times (6.022\times 10^{23})=3.14\times 10^{23} number of ions

Thus, the number of moles of ions form are, 3.14\times 10^{23}

4 0
3 years ago
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