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Svetach [21]
3 years ago
10

A twin-sized air mattress used for camping has dimensions of 75 cm by 225 cm by 17.5 cm when blown up. The weight of the mattres

s is 2 kg How heavy a person, in newtons, could the air mattress support if it is floating in freshwater, with density1000 kg/m^3?
Physics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

2870 N

Explanation:

There are three forces on the mattress.  Weight of the mattress, weight of the person, and buoyancy.

∑F = ma

B - mg - Mg = 0

Buoyancy is equal to the weight of the displaced fluid.

ρVg - mg - Mg = 0

ρV - m = M

Plugging in values:

M = (1000 kg/m³) (0.75 m × 2.25 m × 0.175 m) - 2 kg

M = 293 kg

The person's weight is therefore:

Mg = 293 kg × 9.8 m/s²

Mg = 2870 N

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A 170 kg astronaut (including space suit) acquires a speed of 2.25 m/s by pushing off with his legs from a 2600 kg space capsule
saw5 [17]

Explanation:

Mass of the astronaut, m₁ = 170 kg

Speed of astronaut, v₁ = 2.25 m/s

mass of space capsule, m₂ = 2600 kg

Let v₂ is the speed of the space capsule. It can be calculated using the conservation of momentum as :

initial momentum = final momentum

Since, initial momentum is zero. So,

m_1v_1+m_2v_2=0

170\ kg\times 2.25\ m/s+2600\ kg\times v_2=0

v_2=-0.17\ m/s

So, the change in speed of the space capsule is 0.17 m/s. Hence, this is the required solution.

8 0
3 years ago
A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction
zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, F_c=\frac{mv^2}{R}

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

f=\mu N

As there is no vertical motion, therefore, N=mg. So,

f=\mu mg

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816

Therefore, option (c) is correct.

7 0
3 years ago
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Answer:

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Explanation:

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A boy on a bicycle drags a wagon full of newspapers at 0.80 m/s for 30 min (1800 s) using a force of 40 N. How much work has the
Eva8 [605]

Answer:

N133A

Explanation:black

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Define pressure snd state its SI units to​
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Answer:

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