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Svetach [21]
3 years ago
10

A twin-sized air mattress used for camping has dimensions of 75 cm by 225 cm by 17.5 cm when blown up. The weight of the mattres

s is 2 kg How heavy a person, in newtons, could the air mattress support if it is floating in freshwater, with density1000 kg/m^3?
Physics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

2870 N

Explanation:

There are three forces on the mattress.  Weight of the mattress, weight of the person, and buoyancy.

∑F = ma

B - mg - Mg = 0

Buoyancy is equal to the weight of the displaced fluid.

ρVg - mg - Mg = 0

ρV - m = M

Plugging in values:

M = (1000 kg/m³) (0.75 m × 2.25 m × 0.175 m) - 2 kg

M = 293 kg

The person's weight is therefore:

Mg = 293 kg × 9.8 m/s²

Mg = 2870 N

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Answer:

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Explanation:

Parameters given:

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Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through
Norma-Jean [14]

Answer:

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2.\theta=60.15^{0}

Explanation:

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\sqrt{\frac{163}{327.5} } = sin\theta

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\theta=29.84^{0}

For a larger angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} cos^{2}\theta

\frac{I_{2} }{I_{1} }=Cos^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = cos\theta

\theta=Cos^{-1}(0.4977)

\theta=60.15^{0}

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