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denis-greek [22]
3 years ago
10

Idenify each statement below as either oxidation or reduction.

Chemistry
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

1 = oxidation

2 = reduction

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

2I- ----> I₂+ 2e⁻

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

F + e⁻ ----> F⁻

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

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What is the concentration of h+ ions in a solution of hydrochloric acid that was prepared by diluting 35.0 ml of concentrated (1
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ammonium bromide reacts with copper(i) sulfate in aqueous solution to form a solid precipitate. what is the net ionic equation f
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Answer:

Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)

Explanation:

Hello,

In this case, the molecular chemical reaction is written as:

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In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:

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Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:

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Regards.

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