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denis-greek [22]
3 years ago
10

Idenify each statement below as either oxidation or reduction.

Chemistry
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

1 = oxidation

2 = reduction

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

2I- ----> I₂+ 2e⁻

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

F + e⁻ ----> F⁻

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

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Explanation:

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5 0
3 years ago
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kinetic

Explanation:

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3 0
3 years ago
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Give an example of how environmental science might involve geology and chemistry.
Sever21 [200]
One of the examples is radiation and chemistry of water. Environmental science requires the capacity to integrate data from the greater part of the significant fields of science, and in addition from arithmetic. 
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8 0
3 years ago
How many grams of iron(II) chloride are needed to produce 44.3 g iron(II) phosphate in the presence of excess sodium phosphate?
zalisa [80]

Answer:

47.2 g

Explanation:

Let's consider the following double displacement reaction.

3 FeCl₂ + 2 Na₃PO₄ → Fe₃(PO₄)₂ + 6 NaCl

The molar mass of Fe₃(PO₄)₂ is 357.48 g/mol. The moles corresponding to 44.3 g are:

44.3 g × (1 mol / 357.48 g) = 0.124 mol

The molar ratio of Fe₃(PO₄)₂ to FeCl₂ is 1:3. The moles of FeCl₂ are:

3 × 0.124 mol = 0.372 mol

The molar mass of FeCl₂ is 126.75 g/mol. The mass of FeCl₂ is:

0.372 mol × (126.75 g/mol) = 47.2 g

5 0
3 years ago
. How many grams of NaOH would you need to make 450 mL of a 0.250 M NaOH solution
Stella [2.4K]
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
450 ml= .450 L
.250 = N/.450
N=.1125 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (.1125 mol) =  
4.5g of NaOH.
</span>
Hope it helps. Good luck on chemistry.
7 0
4 years ago
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