<span>Raising
the temperature of the reactants increases the reaction between the reactants.
The kinetic energy of the molecules of the reactants collides more frequently
with ach other thereby increasing its reaction. Increasing the concentration of
the reactants increases the reaction rate. Adding a catalyst to the reaction
increases the rate of reaction of a substance. The catalyst hastens the
chemical reaction. </span>
Answer:
Ethane would have a higher boiling point.
Explanation:
In this case, for the lewis structures, we have to keep in mind that all atoms must have <u>8 electrons</u> (except hydrogen). Additionally, each carbon would have <u>4 valence electrons</u>, with this in mind, for methane we have to put the hydrogens around the carbon, and with this structure, we will have 8 electrons for the carbon. In ethane, we will have a bond between the carbons, therefore we have to put three hydrogens around each carbon to obtain 8 electrons for each carbon.
Now, the main difference between methane and ethane is an <u>additional carbon</u>. In ethane, we have an additional carbon, therefore due to this additional carbon, we will have <u>more area of interaction</u> for ethane. If we have more area of interaction we have to give <u>more energy</u> to the molecule to convert from liquid to gas, so, the ethane will have a higher boiling point.
I hope it helps!
Each shell can contain only a fixed number of electrons: The first shell
can hold up to two electrons, the second shell can hold up to eight (2 +
6) electrons, the third shell can hold up to18 (2 + 6 + 10) and so on.
The general formula is that the nth shell can in principle hold up to
2(n2) electrons.
The answer would be b) GAS
Answer:
0.0833 moles of O₂
Explanation:
Most usual Law to solve this sort of problem, is the Ideal Gases Law
Pressure . Volume = number of moles . R . Temperature
where R is the Ideal Gases Constant → 0.082 L.atm/mol.K
First of all we need to convert the pressure from kPa to atm, because the Units of R
320 kPa . 1 atm / 101.3 kPa = 3.16 atm
Now, you replace data:
3.16 atm . 0.45L = mol . 0.082 L.atm/mol.K . 280K
(3.16 atm . 0.45L) / (0.082 L.atm/mol.K . 280K) = mol
0.0833 moles of O₂
