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Ludmilka [50]
3 years ago
9

What os environment?​

Physics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

is the environment in which users run application software. The environment consists of a user interface provided by an applications manager and usually an application programming interface (API) to the applications manager.

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How many electrons must be removed from each of two 5.69-kg copper spheres to make the electric force of repulsion between them
CaHeK987 [17]

Answer:

n=3.056*10^{9} Electrons

Explanation:

Please see attached file

7 0
3 years ago
Tonya is thinking about the topic presented in the text, "Do opposites really attract?" Which of her thoughts is an example of c
tigry1 [53]

tanya is dumb  j j j j j j j j j jj j j j

6 0
3 years ago
"A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a s
Tamiku [17]

Answer:

The film thickness is 4.32 * 10^-6 m

Explanation:

Here in this question, we are interested in calculating the thickness of the film.

Mathematically;

The number of fringes shifted when we insert a film of refractive index n and thickness L in the Michelson Interferometer is given as;

ΔN = (2L/λ) (n-1)

where λ is the wavelength of the light used

Let’s make L the subject of the formula

(λ * ΔN)/2(n-1) = L

From the question ΔN = 8 , λ = 540 nm, n = 1.5

Plugging these values, we have

L = ((540 * 10^-9 * 8)/2(1.5-1) = (4320 * 10^-9)/1 = 4.32 * 10^-6 m

6 0
3 years ago
What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?
babunello [35]

Answer:

m³/(kg⋅s²)

Explanation:

Hello.

In this case, since the involved formula is:

F=G*\frac{m_1m_2}{r^2}

By writing a dimensional analysis with the proper algebra handling, we obtain:

N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}

Thus, answer is:

m³/(kg⋅s²)

Note that the [=] is used to indicate the units of G.

Best regards

4 0
3 years ago
If a 12 kg cat is sitting 5 m up in a tree, how much PE does it have?
Helen [10]

Answer:

588 J

Explanation:

PE (potential energy) = (mass) x (gravity) x (height)

mass = 12 kg

gravity = 9.8m/s^2

height = 5 m

PE = (12) x (9.8) x (5) = 588 J (Joules)

5 0
2 years ago
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